Predict the product when the given compound reacts with LiAlH₄ :
   

1.		2.
3.		4.

The labeled -O¹⁸ will be:


1. H₂O

2. Methyl benzoate

3. Both 1 and 2

4. Benzoic acid

Identify the major product,

1.     

2.   

3.    

4. 

$\stackrel{{\mathrm{H}}_2{\mathrm{CrO}}_4}{\to }$(A) Product (A) is:   

(a) No reaction

(b) 

(c) 

(d) 

$\underset{\left(2\right)<mspace\; width="1em"></mspace>{\mathrm{H}}^{+},<mspace\; width="1em"></mspace>{\mathrm{H}}_2\mathrm{O}<mspace\; width="1em"></mspace><mspace\; width="1em"></mspace><mspace\; width="1em"></mspace>}{\overset{\left(1\right)<mspace\; width="1em"></mspace>\mathrm{EtLi}<mspace\; width="1em"></mspace>(3.5<mspace\; width="1em"></mspace>\mathrm{eq})}{\to }}<mspace\; width="1em"></mspace>\left(\mathrm{A}\right)<mspace\; width="1em"></mspace>65\%<mspace\; width="1em"></mspace>\mathrm{Yield}<mspace\; width="1em"></mspace>$; Chemist added extra 0.5 mole of Et-Li in above reaction to obtain product (A), which is ?

What is the major product (A) in the following reaction?

1.		2.
3.		4.

$\underset{\mathrm{dimethoxy}<mspace\; width="1em"></mspace>\mathrm{ethane}}{\overset{\mathrm{LiH}}{\to }}$L$\stackrel{{\mathrm{CH}}_3\mathrm{Li}}{\to }$M$\stackrel{{\mathrm{H}}_3{\mathrm{O}}^{+}}{\to }$ N + CH₃OH

Product (N) is:

1. 

2. 

3.       

4. 

$\stackrel{\mathrm{PCC}}{\to }$(A)$\underset{{\mathrm{H}}^{+}}{\overset{\mathrm{OH}-\mathrm{CH}2-\mathrm{CH}2-\mathrm{OH}}{\to }}$(B)$\stackrel{\left(1\right)<mspace\; width="1em"></mspace>\mathrm{MeMgBr}<mspace\; width="1em"></mspace>\left(2\right)<mspace\; width="1em"></mspace>{\mathrm{H}}_3{\mathrm{O}}^{+}}{\to }$
$$(C)$\stackrel{{\mathrm{NaBH}}_4\mathrm{EtOH}}{\to }$(D) Product

(D) in above reaction Is:

(a) 

(b) 

(c) 

(d) 

$\underset{\mathrm{Pyridine}}{\overset{\mathrm{TsCl}}{\to }}$(A)$\stackrel{{\mathrm{LiAlH}}_4}{\to }$(B)    

Product (B) of the above reaction is:

 $CHO$
$<mspace\; width="1em"></mspace>|$
$CH-OH<mspace\; width="1em"></mspace>\stackrel{2Hl{O}_4}{\to }$
$<mspace\; width="1em"></mspace>|$
$C{H}_2-OH$Products obtained in the above reaction are :

(1) HCHO, HCO₂H

(2) HCHO, 2HCO₂H

(3) CO₂, 2HCO₂H

(4) CO₂, HCHO, HCO₂H