E. coli cells with a mutated z gene of the lac operon cannot grow in a medium containing only lactose as the source of energy because-

1. They cannot synthesize functional beta-galactosidase
2. They cannot transport lactose from the medium into the cell
3. The lac operon is constitutively active in these cells
4. In the presence of glucose, E. coli cells do not utilize lactose

Subtopic:  Gene Regulation: Lac Operon |
 75%
Level 2: 60%+
AIPMT - 2005
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Production of a human protein in bacteria by genetic engineering is possible because:

1.  Bacterial cells can carry out the RNA splicing reactions
2.  The mechanism of gene regulation is identical in humans and bacteria
3.  The human chromosome can replicate in bacterial cell
4.  The genetic code is universal
Subtopic:  Genetic Code: III |
 74%
Level 2: 60%+
AIPMT - 2005
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Which of the following exercises control over transcription:
1.  Operator
2.  Regulator
3.  Promoter
4.  Recon

Subtopic:  Gene Regulation: Lac Operon |
Level 3: 35%-60%
AIPMT - 1998
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Variations in proteins are due to:
1.  Sequence of amino acids
2.  Number of amino acids
3.  R–group
4.  None

Subtopic:  Translation |
 74%
Level 2: 60%+
AIPMT - 1998
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A sequence of how many nucleotides in messenger RNA make a codon for an amino acid:

1. Four

2. One

3. Two

4. Three

Subtopic:  Translation |
 86%
Level 1: 80%+
AIPMT - 2004
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DNA fingerprinting refers to:

1. Analysis of DNA samples using imprinting devices
2. Techniques used for molecular analysis of different specimens of DNA
3. Techniques used for the identification of fingerprints of individuals
4. Molecular analysis of profiles of DNA samples

Subtopic:  DNA Fingerprinting |
Level 3: 35%-60%
AIPMT - 2004
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During transcription, if the nucleotide sequence of the DNA strand that is being coded is ATACG, then the nucleotide sequence in the mRNA would be:

1. TCTGG

2. UAUGC

3. UATGC

4. TATGC

Subtopic:  The DNA | DNA Double Helix |
 85%
Level 1: 80%+
AIPMT - 2004
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Number of base pairs in human chromosomes are:

1. 3×109

2. 3×107

3. 6×108

4. 6×107

Subtopic:  The DNA |
 88%
Level 1: 80%+
AIPMT - 1999
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The following ratio is generally constant for a given species:

1. T + C / G + A 2. G + C / A+ T
3. A + C / T + G 4. A + G / C +T
Subtopic:  DNA Double Helix |
 53%
Level 3: 35%-60%
AIPMT - 2004
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Initiation codon in eukaryotes is:
1.  UGA
2.  CCA
3.  AGA
4.  AUG

Subtopic:  Genetic Code: II |
 95%
Level 1: 80%+
AIPMT - 1999
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