If the mass of a bob in a simple pendulum is increased to thrice its original mass and its length is made half its original length, then the new time period of oscillation is \( \dfrac{x}{2}\) times its original time period. The value of \(x\) is:
1. \(\sqrt2\) 2. \(2\sqrt3\)
3. \(4\) 4. \(\sqrt3\)
Subtopic:  Angular SHM |
 68%
Level 2: 60%+
NEET - 2024
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If \(T_1,T_2,T_3,T_4\) and \(T_5\) represent the tension in the string of a simple pendulum when the bob is at the left extreme, right extreme, mean, any intermediate left and any intermediate right positions, respectively. Then, which of the following relations are correct?
(A) \(T_1=T_2\) (B) \(T_3>T_2\)
(C) \(T_4>T_3\) (D) \(T_3=T_4\)
(E) \(T_5>T_2\)
Choose the most appropriate answer from the options given below:
1. (A), (B) and (C) only 2. (B), (C) and (D) only
3. (A), (B) and (E) only 4. (C), (D) and (E) only
Subtopic:  Angular SHM |
 68%
Level 2: 60%+
NEET - 2024
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A simple pendulum oscillating in air has a period of \(\sqrt3\) s. If it is completely immersed in non-viscous liquid, having density \(\left(\dfrac14\right)^{\text{th}}\) of the material of the bob, the new period will be:
1. \(2\sqrt3\) s 2. \(\dfrac{2}{\sqrt3}\) s
3. \(2\) s 4. \(\dfrac{\sqrt 3}{2}\) s
Subtopic:  Angular SHM |
 53%
Level 3: 35%-60%
NEET - 2023
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Two pendulums of length \(121~\text{cm}\) and \(100~\text{cm}\) start vibrating in phase. At some instant, the two are at their mean position in the same phase. The minimum number of vibrations of the shorter pendulum after which the two are again in phase at the mean position is: 
1. \(8\) 2. \(11\)
3. \(9\) 4. \(10\)
Subtopic:  Angular SHM |
 70%
Level 2: 60%+
NEET - 2022
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A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20 m/s2 at a distance of 5 m from the mean position. The time period of oscillation is:

1. 2π s 2. π s
3. 2 s 4. 1 s
Subtopic:  Angular SHM |
 86%
Level 1: 80%+
NEET - 2018
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Two spherical bobs of masses \(M_A\) and \(M_B\) are hung vertically from two strings of length \(l_A\) and \(l_B\) respectively. If they are executing SHM with frequency as per the relation \(f_A=2f_B,\) Then:
1. \(l_A = \frac{l_B}{4}\)
2. \(l_A= 4l_B\)
3. \(l_A= 2l_B~\&~M_A=2M_B\)
4. \(l_A= \frac{l_B}{2}~\&~M_A=\frac{M_B}{2}\)

Subtopic:  Angular SHM |
 75%
Level 2: 60%+
AIPMT - 2000
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The frequency of a simple pendulum in a free-falling lift will be:
1. zero
2. infinite
3. can't say
4. finite

Subtopic:  Angular SHM |
 70%
Level 2: 60%+
AIPMT - 1999
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