What is the difference between 0.50 mol Na₂CO₃ and 0.50 M Na₂CO₃?
| 1. | They represent different amounts of Na₂CO₃. |
| 2. | 0.50 mol represents the amount of Na₂CO₃, whereas 0.50 M represents its molarity. |
| 3. | 0.50 mol Na₂CO₃ produces more ions. |
| 4. | None of the above. |
Round up the following numbers into three significant figures:
(i) 10.4107
(ii) 0.04597
| 1. | 10.4, 0.0460 | 2. | 10.41, 0.046 |
| 3. | 10.0, 0.04 | 4. | 10.4, 0.0467 |
The following data was obtained when dinitrogen and dioxygen react together to form different compounds:
| Mass of dinitrogen | Mass of dioxygen | |
| i. | 14 g | 16 g |
| ii. | 14 g | 32 g |
| iii. | 28 g | 32 g |
| iv. | 28 g | 80 g |
The law of chemical combination applicable to the above experimental data is:
1. Law of reciprocal proportions
2. Law of multiple proportions
3. Law of constant composition
4. None of the above.
Which of the following correctly represents 234,000 and 6.0012 in scientific notation?
| 1. | \(2.34 \times 10^{-9} \text { and } 6 \times 10^3\) |
| 2. | \(0.234 \times 10^{-6} \text { and } 60012 \times 10^{-9}\) |
| 3. | \(2.34 \times 10^{-9} \text { and } 6.0012 \times 10^{-9}\) |
| 4. | \(2.34 \times 10^5 \text { and } 6.0012 \times 10^0\) |
| List-I | List-II | ||
| a. | Micro | i. | m |
| b. | Mega | ii. | m |
| c. | Giga | iii. | m |
| d. | Femto | iv. | m |
| a | b | c | d | |
| 1. | i | iv | iii | ii |
| 2. | iii | iv | ii | i |
| 3. | ii | iii | iv | i |
| 4. | i | iii | iv | ii |
How many grams of HCl are required to react with 5.0 g of manganese dioxide in the reaction provided?
\(4 \mathrm{HCl}_{(\mathrm{aq})}+\mathrm{MnO}_{2(\mathrm{~s})} \rightarrow 2 \mathrm{H}_2 \mathrm{O}_{(\mathrm{l})}+\mathrm{MnCl}_{2(\mathrm{aq})}+\mathrm{Cl}_{2(\mathrm{~g})}\)
1. 4.8 g
2. 6.4 g
3. 2.8 g
4. 8.4 g
Find the mass of CaCO₃ required to completely react with 25 mL of 0.75 M HCl according to the reaction:
CaCO₃(s) + 2HCl(aq) → CaCl₂(aq) + CO₂(g) + H₂O(l)
1. 0.36 g
2. 0.09 g
3. 0.96 g
4. 0.66 g
Burning a small sample of welding gas (constituted of C and H only) in oxygen gives 3.38 g carbon dioxide, 0.690 g of water, and no other products. A volume of 10.0 L (measured at STP) of this welding gas is found to weigh 11.6 g. Molecular formula of welding gas would be:
1. C2H2
2. C2H6
3. CH
4. C2H4
Which of the following contains the highest number of atoms?
1. 52 moles of Ar
2. 52 u of He
3. 52 g of He
4. All of the above have the same number of atoms