If the length of a pendulum is made 9 times and mass of the bob is made 4 times, then the value of time period will become:
1. 3T
2. 3/2T
3. 4T
4. 2T
In a simple pendulum, the period of oscillation T is related to length of the pendulum l as:
1. = constant
2. = constant
3. = constant
4. = constant
A pendulum has time period T. If it is taken on to another planet having acceleration due to gravity half and mass 9 times that of the earth, then its time period on the other planet will be:
1. | \(\sqrt{\mathrm{T}} \) | 2. | \(T \) |
3. | \(\mathrm{T}^{1 / 3} \) | 4. | \(\sqrt{2} \mathrm{~T}\) |
Two spherical bobs of masses \(M_A\) and \(M_B\) are hung vertically from two strings of length \(l_A\) and \(l_B\) respectively. If they are executing SHM with frequency as per the relation \(f_A=2f_B,\) Then:
1.
2.
3.
4.
The frequency of a simple pendulum in a free-falling lift will be:
1. zero
2. infinite
3. can't say
4. finite
A simple pendulum attached to the ceiling of a stationary lift has a time period of 1 s. The distance y covered by the lift moving downward varies with time as y = 3.75 , where y is in meters and t is in seconds. If g = 10 , then the time period of the pendulum will be:
1. | 4 s | 2. | 6 s |
3. | 2 s | 4. | 12 s |
The period of oscillation of a simple pendulum of length \(\mathrm{L}\) suspended from the roof of a vehicle which moves without friction down an inclined plane of inclination , is given by:
1.
2.
3.
4.
A simple pendulum hanging from the ceiling of a stationary lift has a time period T1. When the lift moves downward with constant velocity, then the time period becomes T2. It can be concluded that:
1. | \(T_2 ~\text{is infinity} \) | 2. | \(\mathrm{T}_2>\mathrm{T}_1 \) |
3. | \(\mathrm{T}_2<\mathrm{T}_1 \) | 4. | \(T_2=T_1\) |
Two simple pendulums of length 1 m and 16 m are in the same phase at the mean position at any instant. If T is the time period of the smaller pendulum, then the minimum time after which they will again be in the same phase will be:
1.
2.
3.
4.
A simple pendulum of mass m swings about point B between extreme positions A and C. Net force acting on the bob at these three points is correctly shown by:
1. | 2. | ||
3. | 4. |