The maximum work which can be obtained from a Daniel cell \(Zn_{(s)}\ |\ Zn^{+2}_{(aq)}\ || Cu^{+2}_{(aq)}\ |\ Cu_{(s)}\) is:

\(E^o_{Zn^{2+}/Zn}\) −0.76 V
\(E^o_{Cu^{2+}/Cu}\) 0.34 V

1. +106.15 kJ

2. -212.3 kJ

3. -424.6 kJ

4. +212.3 kJ

Subtopic:  Electrode & Electrode Potential |
 62%
From NCERT
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The quantity of electricity required to reduce 12.3 g of nitrobenzene to aniline with 50 % current efficiency is:

1. 1 F

2. 0.6 F

3. 0.5 F

4. 1.2 F

Subtopic:  Faraday’s Law of Electrolysis |
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When aqueous NaCl solution is electrolysed using inert electrodes then pH of the solution-

1. Increases.

2. Decreases.

3. Remains same.

4. First increases then decreases.

Subtopic:  Electrolytic & Electrochemical Cell |
 58%
From NCERT
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At 298 K the Emf of the following cell is:

\(\small{Pt|H_{2}(1 \ atm)|H^{+}(0.02 \ M) \ || \ H^{+}(0.01 \ M)|H_{2}(1 \ atm)|Pt}\)

1. - 0.017 V

2. 0.0295 V

3. 0.1 V

4. 0.059 V

Subtopic:  Nernst Equation |
 61%
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By how much will the potential of half cell Cu2+| Cu change if the solution is diluted to 100 times at 298 K. It will -

1. Increase by 59 mV 2. Decrease by 59 mV
3. Increase by 29.5 mV 4. Decrease by 29.5 mV
Subtopic:  Nernst Equation |
 57%
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In the electrochemical cell:

Zn|ZnSO4(0.01 M) || CuSO4(1.0M),Cu, the emf of this Daniel cell is E1. When the concentration of ZnSO4 is changed to 1.0 M and that of CuSO4 is changed to 0.01 M, the emf changes to E2. The relationship between E1 and E2 is : 
( Given, RT= 0.059)

1. E1 = E2

2. E1 < E2

3. E1 > E2

4. E2 = 0 ≠ E1

Subtopic:  Electrode & Electrode Potential | Nernst Equation |
 70%
From NCERT
NEET - 2017
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The weight of silver (atomic weight = 108) displaced by a quantity of electricity which displaces 5600 mL of O2 at STP will be : 

1. 5.4 g

2. 10.8 g

3. 54.0 g

4. 108.0 g

Subtopic:  Faraday’s Law of Electrolysis |
 54%
From NCERT
NEET - 2014
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Given the reaction:

\(\mathrm{Cu}(\mathrm{~s})+2 \mathrm{Ag}^{+}(\mathrm{aq}) \rightarrow \mathrm{Cu}^{2+}(\mathrm{aq})+2 \mathrm{Ag}(\mathrm{~s})\) with E° = 0.46 V at 298 K,
what is the equilibrium constant for the reaction?

1. 2.4 x 1010 2. 2.0 x 1010
3. 4.0 x 1010 4. 4.0 x 1015
Subtopic:  Relation between Emf, G, Kc & pH |
 66%
From NCERT
NEET - 2007
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During electrolysis of conc. H2SO4, perdisulphuric acid (H2S2O8), and O2 form in equimolar amount. The amount of H2 that will form simultaneously will be : 

1. Thrice that of O2 in moles.

2. Twice that of O2 in moles.

3. Equal to that of O2 in moles.

4. Half of that of O2 in moles.

Subtopic:  Faraday’s Law of Electrolysis |
From NCERT
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What happens to the voltage in a galvanic cell when the salt bridge is removed?

1. The voltage drops to zero.
2. The voltage remains the same.
3. The voltage gradually increases.
4. The voltage rapidly increases.

Subtopic:  Batteries & Salt Bridge |
 78%
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