For a crystal with \(\lambda = 1~\mathring{A}\) and Bragg's angle \(\theta= 60^{\circ}\), the second-order diffraction, \(d\) (distance between two consecutive atomic layers) will be:
1. \(1.15~\mathring{A}\)
2. \(0.75~\mathring{A}\)
3. \(0.55~\mathring{A}\)
4. \(2.1~\mathring{A}\)
Add Note
Subtopic: Â Diffraction |
 52%
From NCERT
AIPMT - 1998
Other Reason
Highlight in NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Upgrade Your Plan
Upgrade now and unlock your full question bank experience with daily practice.
The interplanar distance in a crystal is \(2.8 \times 10^{-8}~\text{m}\). The value of the maximum wavelength which can be diffracted:
1. \(2.8 \times 10^{-8}~\text{m}\)
2. \(5.6 \times 10^{-8}~\text{m}\)
3. \(1.4 \times 10^{-8}~\text{m}\)
4. \(7.6 \times 10^{-8}~\text{m} \)
Add Note
Subtopic: Â Diffraction |
From NCERT
AIPMT - 2001
Other Reason
Highlight in NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Upgrade Your Plan
Upgrade now and unlock your full question bank experience with daily practice.