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Q. No.Consider the following combination of n, l, and m values.
(i) n=3; l=0; m=0
(ii) n=4; l=0; m=0
(iii) n=3; l=1; m=0
(iv) n=3; l=2; m=0
The correct order of energy of the corresponding orbitals for multielectron species:
1. (ii) > (i)> (iv)> (iii)
2. (iv) > (ii) > (iii) > (i)
3. (i) > (iii) > (iv) > (ii)
4. (iv) > (iii) > (i) > (ii)
(i) n=3; l=0; m=0
(ii) n=4; l=0; m=0
(iii) n=3; l=1; m=0
(iv) n=3; l=2; m=0
The correct order of energy of the corresponding orbitals for multielectron species:
1. (ii) > (i)> (iv)> (iii)
2. (iv) > (ii) > (iii) > (i)
3. (i) > (iii) > (iv) > (ii)
4. (iv) > (iii) > (i) > (ii)
Subtopic: Â Shell & Subshell |
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All of the energy levels listed below are allowed, except one. Find that odd one out:
1. 3f
2. 4d
3. 5p
4. 7s
1. 3f
2. 4d
3. 5p
4. 7s
Subtopic: Â Shell & Subshell |
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Subtopic: Â Shell & Subshell |
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Which of the following electronic configurations for ground state atoms is incorrect?
| 1. |  |
| 2. |  |
| 3. |  |
| 4. |  |
Subtopic: Â Shell & Subshell |
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Match List-I with List-II:
Choose the correct answer from the options given below:
| List-I (quantum number) |
List-II (Orbital) |
||
| (A) | n = 2, \(\ell\) = 1 | (I) | 2s |
| (B) | n = 3, \(\ell\) = 2 | (II) | 3s |
| (C) | n = 3, \(\ell\) = 0 | (III) | 2p |
| (D) | n = 2, \(\ell\) = 0 | (IV) | 3d |
| (A) | (B) | (C) | (D) | |
| 1. | (III) | (IV) | (I) | (II) |
| 2. | (IV) | (III) | (I) | (II) |
| 3. | (IV) | (III) | (II) | (I) |
| 4. | (III) | (IV) | (II) | (I) |
Subtopic: Â Shell & Subshell |
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NEET - 2022
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What is the maximum number of electrons that can fill a specific energy level?
1. \(2n\)
2. \(n\)
3. \(2n^2 + 1 \)
4. \(2n^2\)
1. \(2n\)
2. \(n\)
3. \(2n^2 + 1 \)
4. \(2n^2\)
Subtopic: Â Shell & Subshell |
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Which of the following is the correct order of filling of electrons, in the sixth period?
| 1. | 6s, 5f, 6d, 6p | 2. | 6s, 6p, 6d, 6f |
| 3. | 6s, 5d, 5f, 6p | 4. | 6s, 4f, 5d, 6p |
Subtopic: Â Shell & Subshell |
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The quantum number of four electrons are given below :
| I. | n = 4, l=2 , ml = -2, ms = \(-\frac{1}{2}\) |
| II. | n=3, l=2, ml = 1, ms = \(+\frac{1}{2}\) |
| III. | n=4 , l=1, ml = 0, ms = \(+\frac{1}{2}\) |
| IV. | n=3, l=1, ml=1, ms=\(-\frac{1}{2}\) |
The correct order of their increasing energies will be:
1. I < III < II < IV
2. IV < II < III < I
3. I < II < III < IV
4. IV < III < II < I
Subtopic: Â Shell & Subshell |
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