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Q. No.
Three capacitors each of \({4}~\mu \text{F}\) are to be connected in such a way that the effective capacitance is \({6}~\mu \text{F}.\) This can be done by connecting them:
1. connecting all of them in a series
2. connecting all of them in parallel
3. connecting two in series and one in parallel
4. connecting two in parallel and one in series
Subtopic:  Combination of Capacitors |
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An electrical circuit requires a capacitance of \(2~\mu\text{F}\) across a potential difference of \(1.0~\text{kV}.\) A large number of \(1~\mu\text{F}\) capacitors are available, each of which can withstand a maximum voltage of \(300~\text{V}.\) What is the minimum number of these capacitors needed to achieve the required capacitance and voltage rating?
1. \(2\)
2. \(16\)
3. \(24\)
4. \(32\)

Subtopic:  Combination of Capacitors |
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The equivalent capacitance between \(A\) and \(B \) in the circuit given below is:

1. \(3.6~\mu \text F\)
2. \(2.4~\mu \text F\)
3. \(4.9~\mu \text F\)
4. \(5.4~\mu \text F\)
Subtopic:  Combination of Capacitors |
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The figure shows the charge \((q)\) versus voltage \((V)\) graphs corresponding to two different combinations of the same pair of capacitors:
1. In parallel: \(A\)
2. In series: \(B\)
Based on the graphs (for \(A\) & \(B\)), what are the capacitances of the two capacitors?

1. \(50~ \mu \text{F} \text { and } 30 ~\mu \text{F}\) 2. \(40~ \mu \text{F} \text { and } 10 ~\mu \text{F}\)
3. \(20~ \mu \text{F} \text { and } 30 ~\mu \text{F}\) 4. \(60~ \mu \text{F} \text { and } 40 ~\mu \text{F}\)
Subtopic:  Combination of Capacitors |
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Two equal capacitors are first connected in series and then in parallel. The ratio of the equivalent capacitances, \(\left ( \dfrac{C_{Series}}{C_{Parallel}} \right )\) in these two cases will be:
1. \(4:1\)
2. \(2:1\)
3. \(1:4\)
4. \(1:2\)

Subtopic:  Combination of Capacitors |
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Consider the combination of 2 capacitors \(\mathrm{C}_1\) and \(\mathrm{C}_2\), with \(\mathrm{C}_2>\mathrm{C}_1 \), when connected in parallel, the equivalent capacitance is \(\frac{15}{4}\)times the equivalent capacitance of the same connected in series. Calculate the ratio of capacitors,\(\frac{\mathrm{C}_2}{\mathrm{C}_1}\).
1. \(\frac{15}{11}\)
2. \(\frac{111}{80}\)
3. \(\frac{29}{15}\)
4. None of the above

Subtopic:  Combination of Capacitors |
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The equivalent capacitance between points A and B in the figure (shown below) will be:

    

1. \(2~\mu \text F\)
2. \(4~\mu \text F\)
3. \(6~\mu \text F\)
4. \(8~\mu \text F\)
Subtopic:  Combination of Capacitors |
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Two metallic plates form a parallel plate capacitor. The distance between the plates is \(d\). A metal sheet of thickness \( d \over 2\) and area equal to the area of each plate is introduced between the plates. What will be the ratio of the new capacitance to the original capacitance of the capacitor?
1. \(2:1\)
2. \(1:2\)
3. \(1:4\)
4. \(4:1\)
Subtopic:  Combination of Capacitors |
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Two capacitors having capacitance \(C_1\) and \(C_2\) respectively are connected as shown in the figure. Initially, capacitor \(C_1\) is charged to a potential difference \(V\) volt by a battery. The battery is then removed and the charged capacitor \(C_1\) is now connected to uncharged capacitor \(C_2\) by closing the switch \(S\). The amount of charge on the capacitor \(C_2\), after equilibrium, is: 
           
1. \(\dfrac{C_1 C_2}{\left(C_1+C_2\right)} V \)

2. \(\dfrac{\left(C_1+C_2\right)}{C_1 C_2} V \)

3. \(\left({C}_1+{C}_2\right) {V} \)

4. \(\left({C}_1-{C}_2\right) {V}\)
Subtopic:  Combination of Capacitors |
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The charge on the capacitor of capacitance \(15~ \mu \text F\) in the figure given below is: 
1. \(60~ \mu\text C\) 2. \(130 ~\mu\text C\)
3. \(260~ \mu \text C\) 4. \(585 ~\mu \text C\)
Subtopic:  Combination of Capacitors |
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