What is the correct order of melting points for hydrides in Group 16?

1. \(H_2S<H_2Se<H_2Te<H_2O\)
2. \(H_2O<H_2S<H_2Se<H_2Te\)
3. \(H_2S<H_2Te<H_2Se<H_2O\)
4. \(H_2Se<H_2S<H_2Te<H_2O\)

Subtopic:  Group 16 - Preparation, Properties & Uses |
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Given below are two statements:
Statement I: The pentavalent oxide of group \(15\) element, \(\mathrm{E_2O_5,}\) is less acidic than the trivalent oxide, \(\mathrm{E_2O_3,}\) of the same element.
Statement II: The acidic character of trivalent oxide of group \(15\) elements, \(\mathrm{E_2O_3,}\) decreases down the group.
 
1. Statement I is incorrect and Statement II is correct.
2. Both Statement I and Statement II are correct.
3. Both Statement I and Statement II are incorrect.
4. Statement I is correct and Statement II is incorrect.
Subtopic:  Group 15 - Preparation, Properties & Uses |
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Chalcogen group elements are:
1. \(O,~Ti\) and \(Po\)
2. \(Se, ~Te\) and \(Po\)
3. \(Se,~ Tb\) and \(Pu\)
4. \(S, ~Te\) and \(Pm\)
Subtopic:  Group 16 - Preparation, Properties & Uses |
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How many interhalogens among those given below have a square pyramidal structure?
\(\mathrm{ClF}_3, \mathrm{IF}_7, \mathrm{BrF}_5, \mathrm{BrF}_3, \mathrm{I}_2 \mathrm{Cl}_6, \mathrm{IF}_5, \mathrm{CIF}, \mathrm{ClF}_5\)
1. 3 2. 5
3. 2 4. 4
Subtopic:  Group 17 - Preparation, Properties & Uses |
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The large difference between the melting and boiling points of oxygen and sulphur may be explained based on:
1. Atomic size
2. Atomicity
3. Electronegativity
4. Electron gain enthalpy
Subtopic:  Group 16 - Preparation, Properties & Uses |
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Consider the given two statements:
Assertion (A): \(\mathrm{NH}_3\) is more polar than \(\mathrm{NF}_3 .\)
Reason (R): The N – H dipole is directed towards N while in the case of \(\mathrm{NF}_3 \), towards F, as F is more electronegative.
Options:
1. Both (A) and (R) are True and (R) is the correct explanation for (A).
2. Both (A) and (R) are True but (R) is not the correct explanation for (A).
3. (A) is True but (R) is False.
4. (A) is False but (R) is True
Subtopic:  Group 15 - Preparation, Properties & Uses |
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Chloride salt of M is treated with excess of AgNO3. It forms curdy white precipitate ‘A’. When ‘A’ is treated with NH4OH, it forms a soluble salt ‘B’. The A and B respectively are:


1. AgCl, [Ag(NH3)2]+
2. AgBr, [Ag(OH)2]
3. AgCl, [Ag(OH)4]2−
4. AgBr, [Ag(OH)4]2−
Subtopic:  Group 15 - Preparation, Properties & Uses |
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Consider the following condition,
(i). X: Oxidation number of Br in bromic acid.
(ii). Y: Oxidation number of Br in perbromic acid.

The value of (X+Y) is:

1. 10 
2. -1
3. 12
4. 8
Subtopic:  Group 17 - Preparation, Properties & Uses |
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Statement I: Chlorine easily forms oxides and the compounds are explosive.
Statement II: The higher oxidation states of chlorine, bromine, and iodine are released when halogens form oxides and fluorides. 
 
1.  Statement I is correct but Statement II is incorrect. 
2.  Statement I is incorrect but Statement II is correct. 
3.  Both Statement I and Statement II are correct.
4.  Both Statement I and Statement II are incorrect.
Subtopic:  Group 17 - Preparation, Properties & Uses |
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Which of the following oxoacids can reduce AgNO3?

1. (HPO3)n
2. H4P2O7
3. H4P2O5
4. H3PO4
Subtopic:  Group 15 - Preparation, Properties & Uses |
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