Calculate the maximum ionic character possible in a bond between two atoms in the periodic table according to Hanny Smith equation. [Electronegativeity of Li=1.0, Na=0.9, K=0.8, Rb=0.8, Cs=0.7, Fr=0.7]
1.
2.
3.
4.
Assertion (A): | PCl3Br2 has zero dipole moment. |
Reason (R): | Br atoms occupy axial position while Cl atoms occupy equatorial position. |
1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
3. | (A) is True but (R) is False. |
4. | Both (A) and (R) are False. |
1. | |
2. | NH3 < NF3 |
3. | Trans-1-fluoro propene < Cis -1-fluoro propene |
4. | SbH3 < PH3 |
Assertion: Dipole moment of cis-1-chloropropene is more than trans-1-chloropropene
Reason: In the case of cis-1-chloropropene, dipoles are additive while in the case of trans-1-chloropropene dipoles are subtractive.
1. Both assertion and reason are true, and the reason is the correct explanation of the assertion
2. Both assertion and reason are true, but the reason is not the correct explanation of the assertion
3. Assertion is true but reason is false
4. Both assertion and reason are false
Case Study Question:
The relative location of the bond pair and the lone pair is decided by Bent's rule. The rule states that the more electronegative atom prefers to stay in the orbital having less s character while the lone pair prefers to stay in the orbital having more s character. In molecules with trigonal bipyramidal (TBP) geometry, the more electronegative atom prefers the axial position while the lone pair prefers the equatorial position.
Which molecule, among the following, has non-zero dipole moment?
1. PCl3F2
2. PCl3Br2
3. PCl3(CH3)2
4. Both (2) and (3)