Select Chapter Topics:
Q. No.The mass of a 2.5 mL solution (the density of the solution is 2.15 g/mL) in the correct significant figures is:
1.
5375 × 10–3 g
2.
5.4 g
3.
5.38 g
4.
53.75 g
Subtopic: Introduction |
73%
Level 2: 60%+
NEET - 2022
Hints
Unlock IMPORTANT QUESTION
This question was bookmarked by 5 NEET 2025 toppers during their NEETprep journey. Get Target Batch to see this question.
✨ Perfect for quick revision & accuracy boost
Buy Target Batch
Access all premium questions instantly
What fraction of Fe exists as Fe(III) in Fe0.96O?
(Consider Fe0.96 to be made up of Fe(II) and Fe(III) only)
1. \(\dfrac{1}{12}\)
2. \(0.08\)
3. \(\dfrac{1}{16}\)
4. \(\dfrac{1}{20}\)
(Consider Fe0.96 to be made up of Fe(II) and Fe(III) only)
1. \(\dfrac{1}{12}\)
2. \(0.08\)
3. \(\dfrac{1}{16}\)
4. \(\dfrac{1}{20}\)
Subtopic: Moles, Atoms & Electrons |
Level 3: 35%-60%
NEET - 2022
Hints
Match List-I with List-II:
| List-I (Quantities) |
List-II (Corresponding Values) |
||
| (a) | 4.48 litres of O2 at STP | (i) | 0.2 mole |
| (b) | 12.022 × 1022 molecules of H2O | (ii) | 12.044 × 1023 molecules |
| (c) | 96 g of O2 | (iii) | 6.4 g |
| (d) | 88 g of CO2 | (iv) | 67.2 litres at STP |
Choose the correct answer from the options given below:
| (a) | (b) | (c) | (d) | |
| 1. | (i) | (iii) | (iv) | (ii) |
| 2. | (iii) | (i) | (iv) | (ii) |
| 3. | (iv) | (i) | (ii) | (iii) |
| 4. | (iii) | (i) | (ii) | (iv) |
Subtopic: Moles, Atoms & Electrons |
50%
Level 3: 35%-60%
NEET - 2022
Hints
Calculate the mass of 95% pure CaCO3 that will be required to neutralize 50 mL of 0.5 M HCl solution according to the following reaction.
CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + 2H2O(l)
[Calculate up to the second place of decimal point]
CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + 2H2O(l)
[Calculate up to the second place of decimal point]
| 1. | 9.50 g | 2. | 1.25 g |
| 3. | 1.32 g | 4. | 3.65 g |
Subtopic: Equation Based Problem |
55%
Level 3: 35%-60%
NEET - 2022
Hints
The mass of CO2 produced by heating 20 g of 20% pure limestone, as per the equation given below, is:\(\mathrm{CaCO}_3(\mathrm{~s}) \xrightarrow{\text { heat }} \mathrm{CaO}(s)+\mathrm{CO}_2(\mathrm{~g})\)
| 1. | 1.32 g | 2. | 1.12 g |
| 3. | 1.76 g | 4. | 2.64 g |
Subtopic: Equation Based Problem |
76%
Level 2: 60%+
NEET - 2023
Hints
Select the correct statements from the following:
Choose the correct answer from the options given below:
| A: | Atoms of all elements are composed of two fundamental particles. |
| B: | The mass of the electron is \(9.10939 \times 10^{-31} \mathrm{~kg} \text {. }\) |
| C: | All the isotopes of a given element show the same chemical properties. |
| D: | Protons and electrons are collectively known as nucleons. |
| E: | Dalton's atomic theory regarded the atom as an ultimate particle of matter. |
| 1. | B, C and E only | 2. | A, B and C only |
| 3. | C, D and E only | 4. | A and E only |
Subtopic: Introduction |
76%
Level 2: 60%+
NEET - 2023
Hints
A 1 M solution of a compound 'X' has a density of 1.25 g/mL. If the molar mass of compound X is 85 g, what is the molality (m) of the solution?
| 1. | 0.705 m | 2. | 1.208 m |
| 3. | 1.165 m | 4. | 0.858 m |
Subtopic: Concentration Based Problem |
68%
Level 2: 60%+
NEET - 2023
Hints
An organic compound contains 80 % (by wt.) carbon and the remaining percentage of hydrogen. The empirical formula of this compound is:
[Atomic wt. of C is 12, H is 1]
1. CH3
2. CH4
3. CH
4. CH2
Subtopic: Empirical & Molecular Formula |
75%
Level 2: 60%+
NEET - 2021
Hints
Unlock IMPORTANT QUESTION
This question was bookmarked by 5 NEET 2025 toppers during their NEETprep journey. Get Target Batch to see this question.
✨ Perfect for quick revision & accuracy boost
Buy Target Batch
Access all premium questions instantly
In the Haber process, 30 litres of dihydrogen and 30 litres of dinitrogen were taken for the reaction which yielded only 50% of the expected product. What will be the composition of a gaseous mixture under the above condition in the end:
| 1. | 20 litres of ammonia, 20 litres of nitrogen, 20 litres of hydrogen |
| 2. | 10 litres of ammonia, 25 litres nitrogen, 15 litres of hydrogen |
| 3. | 20 litres of ammonia, 10 litres of nitrogen, 30 litres of hydrogen |
| 4. | 20 litres of ammonia, 25 litres of nitrogen, 15 litres of hydrogen |
Subtopic: Limiting Reagent |
68%
Level 2: 60%+
AIPMT - 2003
Hints
Unlock IMPORTANT QUESTION
This question was bookmarked by 5 NEET 2025 toppers during their NEETprep journey. Get Target Batch to see this question.
✨ Perfect for quick revision & accuracy boost
Buy Target Batch
Access all premium questions instantly
The specific volume of cylindrical virus particle is hose radius and length are 7 Å & 10Å respectively. If \(\text{mol}^{-1}\), find the molecular weight.
1. \( 15.4 \mathrm{~kg} / \mathrm{mol} \)
2. \(1.54 \times 10^4 \mathrm{~kg} / \mathrm{mol} \)
3. \( 3.08 \times 10^4 \mathrm{~kg} / \mathrm{mol}\)
4. \(3.08 \times 10^3 \mathrm{~kg} / \mathrm{mol}\)
Subtopic: Moles, Atoms & Electrons |
Level 3: 35%-60%
AIPMT - 2001
Hints
Select Chapter Topics:
© 2026 GoodEd Technologies Pvt. Ltd.