- 1(current)
Q. No.There are two inclined surfaces of equal length \((L)\) and same angle of inclination \(45^\circ\) with the horizontal. One of them is rough and the other is perfectly smooth. A given body takes \(2\) times as much time to slide down on rough surface than on the smooth surface. The coefficient of kinetic friction \((\mu_k)\) between the object and the rough surface is close to:
1. \(0.5\)
2. \(0.75\)
3. \(0.25\)
4. \(0.40\)
1. \(0.5\)
2. \(0.75\)
3. \(0.25\)
4. \(0.40\)
Subtopic: Friction |
From NCERT
NEET - 2025
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Hints
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Calculate the maximum acceleration of a moving car so that a body lying on the floor of the car remains stationary. The coefficient of static friction between the body and the floor is \(0.15\). (take \(g=10\) ms–2)
| 1. | \(50\) ms–2 | 2. | \(1.2\) ms–2 |
| 3. | \(150\) ms–2 | 4. | \(1.5\) ms–2 |
Subtopic: Friction |
82%
From NCERT
NEET - 2023
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A block of mass \(2\) kg is placed on inclined rough surface \(AC\) (as shown in the figure) of coefficient of friction \(\mu.\) If \(g=10\) ms–1, the net force (in N) on the block will be:
1. \(10\sqrt3\)
2. zero
3. \(10\)
4. \(20\)
1. \(10\sqrt3\)
2. zero
3. \(10\)
4. \(20\)
Subtopic: Friction |
67%
From NCERT
NEET - 2023
To view explanation, please take trial in the course.
NEET 2026 - Target Batch - Vital
Hints
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NEET 2026 - Target Batch - Vital
Calculate the acceleration of the block and trolly system shown in the figure. The coefficient of kinetic friction between the trolly and the surface is \(0.05.\)
( \(g=10~\text{m/s}^2,\) the mass of the string is negligible and no other friction exists)
| 1. | \( 1.25~\text{m/s}^2\) | 2. | \( 1.50~\text{m/s}^2\) |
| 3. | \(1.66~\text{m/s}^2\) | 4. | \( 1.00~\text{m/s}^2\) |
Subtopic: Friction |
66%
From NCERT
NEET - 2020
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NEET 2026 - Target Batch - Vital
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A body of mass \(m\) is kept on a rough horizontal surface (coefficient of friction = \(\mu).\) A horizontal force is applied to the body, but it does not move. The resultant of normal reaction and the frictional force acting on the object is given by \(\vec {F}\) where:
1. \(|{\vec {F}}| = mg+\mu mg\)
2. \(|\vec {F}| =\mu mg\)
3. \(|\vec {F}| \le mg\sqrt{1+\mu^2}\)
4. \(|\vec{F}| = mg\)
Subtopic: Friction |
75%
From NCERT
NEET - 2019
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NEET 2026 - Target Batch - Vital
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NEET 2026 - Target Batch - Vital
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