In any fission process the ratio

$\frac{\text{ mass of fission products }}{\text{ mass of parent nucleus }}\text{ is:}$

1. Greater than 1

2. Depends on the mass of the parent nucleus

3. Equal to 1

4. Less than 1

Fission of nuclei is possible because the binding energy per nucleon in them:
 

Nuclear – fission is best explained by:

1. Liquid droplet theory

2. Yukawa $\pi$ - meson theory

3. Independent particle model of the nucleus

4. Proton-proton cycle

For the nuclear reaction:

${}_{92}U_{235}$ $+$ ${}_{0}n_1$ $\to$ ${}_{56}B{a}^{144}$ $$ $+$ $...$ $$ $+$ $3_0{n}^1$

The blank space can be filled by:

1. ${}_{26}K{r}^{89}$

2.  ${}_{36}K{r}^{89}$

3. ${}_{26}S{r}^{90}$

4.  ${}_{38}S{r}^{89}$

${}_{n}X_m$ emitted one $\alpha and\mathrm{2 }\beta$ particles, then it will become: 

1. ${}_{n}X_{m-4}$

2. ${}_{n-1}X_{m-1}$

3. ${}_{n}Z_{m-4}$

4. None of these

When X → $$\(N_{7}^{14}\)  + 2\(\beta^{-} \) then the number of neutrons in X will be:
1. 3
2. 5
3. 7
4. 9

If in a nuclear fusion process. the masses of the fusing nuclei be \(m_1\) and \(m_2\) and the mass of the resultant nucleus be \(m_3,\) then:

A nucleus represented by the symbol ${}_{\mathrm{Z}}{}^{\mathrm{A}}\mathrm{X}$ has:

M_P denotes the mass of a proton and M_n that of a neutron. A given nucleus, of binding energy B, contains Z protons and N neutrons. The mass M(N, Z) of the nucleus is given by:
(c is the velocity of light )

1. M(N, Z) = NM_n + ZM_P + Bc²

2. M(N, Z) = NM_n + ZM_P – B/c²

3. M(N, Z) = NM_n + ZM_P + B/c²

4. M(N, Z) = NM_n + ZM_P – Bc²

If a radioactive element emitted one α and one β-particle, then the mass number of the daughter element is:

1.  decreased by 4

2.  increased by 4

3.  decreased by 2

4.  increased by 2