In an interference experiment, the ratio of the amplitudes of two coherent waves is \(\dfrac{a_1}{a_2}=\dfrac{1}{3}.\) The ratio of the maximum and minimum intensities of the fringes will be:

1. \(9\) 2. \(2\)
3. \(18\) 4. \(4\)
Subtopic:  Superposition Principle |
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Two coherent sources produce waves of different intensities which interfere. After interference, the ratio of the maximum intensity to the minimum intensity is \(16.\) The intensity of the waves are in the ratio:
1. \(16:9\)
2. \(25:9\)
3. \(4:1\)
4. \(5:3\)
Subtopic:  Superposition Principle |
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Interference fringes are observed on a screen by illuminating two thin slits \(1\) mm apart with a light source (\(\lambda =632.8~\mathrm{nm}\)). The distance between the screen and the slits is \(100\) cm. If a bright fringe is observed on a screen at a distance of \(1.27\) mm from the central bright fringe, then the path difference between the waves, which are reaching this point from the slits is close to:
1. \(1.27~\mathrm{\mu m}\)
2. \(2~\mathrm{nm}\)
3. \(2.87~\mathrm{nm}\)
4. \(2.05~\mathrm{\mu m}\)
 

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Two coherent sources of sound, \(S_1\) and \(S_2\), produce sound waves of the same wavelength, \(\lambda=1~\mathrm{m}\), in phase. \(S_1\) and \(S_2\) are placed \(1.5\) m apart (see fig.) A listener, located at \(L\), directly in front of \(S_2\) finds that the intensity is at a minimum when he is \(2\) m away from \(S_2\). The listener moves away from \(S_1\), keeping his distance from \(S_2\) fixed. The adjacent maximum of intensity is observed when the listener is at a distance \(d\) from \(S_1\). Then, \(d\) is:

 

1. \(12~\text{m}\)
2. \(3~\text{m}\)
3. \(5~\text{m}\)
4. \(2~\text{m}\)

Subtopic:  Superposition Principle |
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In the figure below, \(P\) and \(Q\) are two equally intense coherent sources emitting radiation of wavelength \(20~\text{m}.\) The separation between \(P\) and \(Q\) is \(5~\text{m}\) and the phase of \(P\) is ahead of that of \(Q\) by \(90^\circ.\) \(A,\) \(B\) and \(C\) are three distinct points of observation each equidistant from the midpoint of \(PQ.\) The intensities of radiation at \(A,\) \(B,\) \(C\) will be ratio: 

                       
1. \(4:1:0\)
2. \(2:1:0\)
3. \(0:1:2\)
4. \(0:1:4\)

Subtopic:  Superposition Principle |
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Two coherent light sources produce an interference pattern, with their intensities in the ratio of \(2x.\) What is the value of the ratio \(\dfrac{{I}_{\max }-{I}_{\min }}{{I}_{\max }+{I}_{\min }}\text{?}\)
1. \( \dfrac{2 \sqrt{2 x}}{x+1} \)
2. \(\dfrac{\sqrt{2 x}}{2 x+1} \)
3. \(\dfrac{\sqrt{2 x}}{x+1} \)
4. \(\dfrac{2 \sqrt{2 x}}{2 x+1}\)

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Two light beams of intensities in the ratio of 9: 4 are allowed to interfere. The ratio of the intensity of maxima and minima will be:
1. 2: 3 
2. 16: 81 
3. 25: 169 
4. 25: 1 
Subtopic:  Superposition Principle |
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The two light beams having intensities I and 9I interfere to produce a fringe pattern on a screen. The phase difference between the beams is \({\pi \over 2}\) at point P and \(\pi\) at point Q. Then the difference between the resultant intensities at P and Q will be: 
1. \(2~\text I\)
2. \(6~\text I\) 
3. \(5~\text I\)
4. \(7~\text I\)
Subtopic:  Superposition Principle |
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The interference pattern is obtained with two coherent light sources of intensity ratio 4 :1. And the ratio \(\frac{I_{\max }+I_{\min }}{I_{\max }-I_{\min }} \text { is } \frac{5}{x}\).  Then, the value of x will be equal to:
1. 3
2. 4
3. 2
4. 1
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In Young’s double slit experiment, the two slits are \(0.6\) mm distance apart. The interference pattern is observed on a screen at a distance of \(80\) cm from the slits. The first dark fringe is observed on the screen directly opposite to one of the slits. The wavelength of light will be:
1. \(450\) nm
2. \(550\) nm
3. \(650\) nm
4. \(750\) nm
Subtopic:  Superposition Principle |
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