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Q. No.A charge \(q\) is placed at the center of the line joining two equal charges \(Q.\) The system of the three charges will be in equilibrium if \(q\) is equal to:
1. \(-Q/4\)
2. \(Q/4\)
3. \(-Q/2\)
4. \(Q/2\)
Subtopic: Coulomb's Law |
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From NCERT
NEET - 2013
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If \(\oint_s \vec{E} \cdot \overrightarrow{d S}=0\) over a surface, then:
| 1. | the electric field inside the surface is necessarily uniform. |
| 2. | the number of flux lines entering the surface must be equal to the number of flux lines leaving it. |
| 3. | the magnitude of electric field on the surface is constant. |
| 4. | all the charges must necessarily be inside the surface. |
Subtopic: Gauss's Law |
78%
From NCERT
NEET - 2023
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Three charged particles having charges equal to \(+1\) C, \(-2\) C and \(+3\) C are placed on the \(x\)-axis at \(x=1\) cm, \(2\) cm, \(3\) cm respectively. Consider a sphere of radius \(10\) cm centred at the origin.
The magnitude of the flux of the electric field of these charges through the sphere is, numerically:
The magnitude of the flux of the electric field of these charges through the sphere is, numerically:
| 1. | slightly greater than \(\frac{2}{\varepsilon_0}\) |
| 2. | slightly less than \(\frac{2}{\varepsilon_0}\) |
| 3. | exactly equal to \(\frac{2}{\varepsilon_0}\) |
| 4. | exactly equal to \(-\frac{2}{\varepsilon_0}\) |
Subtopic: Gauss's Law |
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From NCERT
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The electric field, at the centre of a square with charges placed at its four vertices as shown in the figure, is:
\(\Big(k=\frac{1}{4\pi\varepsilon_0}\Big)~\)
1. zero
2. \(4\frac{kq}{a^2}\)
3. \(2\frac{kq}{a^2}\)
4. \(2\sqrt2\frac{kq}{a^2}\)
\(\Big(k=\frac{1}{4\pi\varepsilon_0}\Big)~\)
1. zero
2. \(4\frac{kq}{a^2}\)
3. \(2\frac{kq}{a^2}\)
4. \(2\sqrt2\frac{kq}{a^2}\)
Subtopic: Electric Field |
71%
From NCERT
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Two point charges \({-q}\) and \({+q}\) are placed at a distance of \({L},\) as shown in the figure.
The magnitude of electric field intensity at a distance \({R}~({R}>>{L})\) varies as:
The magnitude of electric field intensity at a distance \({R}~({R}>>{L})\) varies as:
| 1. | \(\frac{1}{{R}^{6}}\) | 2. | \(\frac{1}{{R}^{2}}\) |
| 3. | \(\frac{1}{{R}^{3}}\) | 4. | \(\frac{1}{{R}^{4}}\) |
Subtopic: Electric Dipole |
70%
From NCERT
NEET - 2022
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Four charges \(q,q\) and \(-q,-q\) are placed at the four vertices of a square of side \(a,\) with like charges across a diagonal. The electric field at the centre of the square is: \((k=\frac{1}{4\pi\varepsilon_0})\)
1. zero
2. \(\sqrt2\frac{kq}{a^2}\)
3. \(2\frac{kq}{a^2}\)
4. \(4\frac{kq}{a^2}\)
1. zero
2. \(\sqrt2\frac{kq}{a^2}\)
3. \(2\frac{kq}{a^2}\)
4. \(4\frac{kq}{a^2}\)
Subtopic: Electric Field |
81%
From NCERT
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Equal and opposite charges are placed at the two vertices of an equilateral triangle, giving a dipole moment \(p.\) A small dipole \(p'\) is placed at the third vertex, parallel to the previous dipole. If the electric fields due to both dipoles \(p,~p',\) at the mid-point of the dipole \(p,\) are equal, then \(\frac{p'}{p}\) equals:
1. \(3\sqrt3\)
2. \(\frac{3\sqrt3}{2}\)
3. \(\sqrt3\)
4. \(\frac{\sqrt3}{2}\)
1. \(3\sqrt3\)
2. \(\frac{3\sqrt3}{2}\)
3. \(\sqrt3\)
4. \(\frac{\sqrt3}{2}\)
Subtopic: Electric Dipole |
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Which of the following field configurations is/are possible?
Note: A, B, C are conductors. Other charges may be present in the vicinity.
1. I, III
2. II
3. I, II, III
4. none of I, II, III
Note: A, B, C are conductors. Other charges may be present in the vicinity.
1. I, III
2. II
3. I, II, III
4. none of I, II, III
Subtopic: Electric Field |
From NCERT
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Identical point charges (\(q\) each), are placed at the eight corners of a cube of side \(a.\) When one of the charges is removed, the electric field at the center becomes \(E_c.\)
Now, identical point charges (same magnitude \(q\) each), are placed at the four corners of a square of side \(a.\) When one of the charges is removed, the electric field at the center becomes \(E_s.\) Then,
1. \(\frac{E_s}{2}=\frac{E_C}{3}\)
2. \(\frac{E_s}{3}=\frac{E_C}{2}\)
3. \(\frac{E_s}{\sqrt2}=\frac{E_C}{\sqrt3}\)
4. \(\frac{E_s}{\sqrt3}=\frac{E_C}{\sqrt2}\)
Now, identical point charges (same magnitude \(q\) each), are placed at the four corners of a square of side \(a.\) When one of the charges is removed, the electric field at the center becomes \(E_s.\) Then,
1. \(\frac{E_s}{2}=\frac{E_C}{3}\)
2. \(\frac{E_s}{3}=\frac{E_C}{2}\)
3. \(\frac{E_s}{\sqrt2}=\frac{E_C}{\sqrt3}\)
4. \(\frac{E_s}{\sqrt3}=\frac{E_C}{\sqrt2}\)
Subtopic: Electric Field |
62%
From NCERT
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Three charges \(q,~q,~-q\) are placed at the three corners of an equilateral triangle ABC, of side \(a.\)
The mid-point of side AB is P while the circumcenter of ABC is O. Let the electric field at P be \(E_p\) and that at O be \(E_O.\)
Then, \(E_O:E_P=\)
1. \(\frac{2}{9}\)
2. \(\frac{4}{9}\)
3. \(\frac{9}{2}\)
4. \(\frac{9}{4}\)
The mid-point of side AB is P while the circumcenter of ABC is O. Let the electric field at P be \(E_p\) and that at O be \(E_O.\)
Then, \(E_O:E_P=\)
1. \(\frac{2}{9}\)
2. \(\frac{4}{9}\)
3. \(\frac{9}{2}\)
4. \(\frac{9}{4}\)
Subtopic: Electric Field |
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