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Q. No.| 1. | \(\Delta Q=\Delta U+\Delta W\) |
| 2. | \(\Delta U=\Delta Q+\Delta W\) |
| 3. | \(\Delta U=\Delta Q-\Delta W\) |
| 4. | \(\Delta U+\Delta Q+\Delta W=0\) |
| 1. | work done by the system is \(120\) J. |
| 2. | work done on the system is \(120\) J. |
| 3. | work done by the system is \(80\) J. |
| 4. | work done on the system is \(80\) J. |
If an average person jogs, he produces \(14.5 \times10^3\) cal/min. This is removed by the evaporation of sweat. The amount of sweat evaporated per minute (assuming \(1\) kg requires \(580 \times10^3\) cal for evaporation) is:
1. \(0.25\) kg
2. \(0.50\) kg
3. \(0.025\) kg
4. \(0.20\) kg
\(1\) g of water of volume \(1\) cm3 at \(100^\circ \text{C}\) is converted into steam at the same temperature under normal atmospheric pressure \(\approx 1\times10^{5} \) Pa. The volume of steam formed equals \(1671\) cm3. If the specific latent heat of vaporization of water is \(2256\) J/g, the change in internal energy is:
1. \(2423\) J
2. \(2089\) J
3. \(167\) J
4. \(2256\) J
1. \(U_0\mathrm{ln}(2)\)
2. \(\frac12U_0~\mathrm{ln}(2)\)
3. \(\frac13U_0~\mathrm{ln}(2)\)
4. \(\frac23U_0~\mathrm{ln}(2)\)
The first law of thermodynamics is a statement of:
| 1. | conservation of heat |
| 2. | conservation of work |
| 3. | conservation of momentum |
| 4. | conservation of energy |
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