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Q. No.A uniform ladder of mass \(10\) kg is placed at an angle against a frictionless vertical wall, as shown in the figure, by applying a horizontal force \(F\) at the bottom \((B)\) of the ladder, towards the wall. (Take \(g=10\) m/s2).
Assume that the ground is frictionless. The force \(F\) equals:
Assume that the ground is frictionless. The force \(F\) equals:
| 1. | \(100\sqrt3\) N | 2. | \(50\sqrt3\) N |
| 3. | \(\dfrac{100}{\sqrt3}\) N | 4. | \(\dfrac{50}{\sqrt3}\) N |
Subtopic: Â Torque |
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A block \(A\) is pushed on a smooth horizontal plane by applying a horizontal force \(F ,\) which causes an acceleration of \({\dfrac g 4}\) (\(g\): acceleration due to gravity). The block does not topple, even though the force acts at its highest point. The normal reaction shifts forward by:
| 1. | \({\dfrac b 2}\) | 2. | \({ \dfrac b 4}\) |
| 3. | \({\dfrac b 8}\) | 4. | \(\dfrac b 3\) |
Subtopic: Â Torque |
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A uniform cylinder of mass \(M,\) radius \(R\) and height \(3R\) is placed upright on a horizontal surface. A particle of mass \(m\) is placed on the top of the cylinder at its edge. For what minimum value of \(m\) will the cylinder topple?
| 1. | \(m = 3M\) |
| 2. | \(m= \dfrac {M}{3}\) |
| 3. | \(m= \dfrac {3M }{2}\) |
| 4. | No value of \(m\) will cause the cylinder to topple. |
Subtopic: Â Torque |
From NCERT
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A horizontal force \(F\) is applied to a uniform solid sphere at rest, so that its line of action passes through the mid-point (\(P\)) of the vertical radius \(OA;O\) being the centre of the sphere (mass : \(m\)). The acceleration of the uppermost point \(A\) is:
| 1. | equal to \(\dfrac{F}{m}.\) |
| 2. | greater than \(\dfrac{F}{m}.\) |
| 3. | less than \(\dfrac{F}{m}.\) |
| 4. | unpredictable, and depends on the radius of the sphere. |
Subtopic: Â Torque |
 57%
From NCERT
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