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Q. No.A bicyclist comes to a skidding stop in \(10\) m. During this process, the force on the bicycle due to the road is \(200\) N is directly opposed to the motion. The work done by the cycle on the road is:
1. \(+2000\) J
2. \(-200\) J
3. zero
4. \(-20000\) J
Subtopic: Â Work done by constant force |
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The work done by gravity on a projectile of mass \(m\) fired with a speed \(u\) at an angle \(\theta\) to the horizontal, until the time of impact is:
| 1. | zero | 2. | \(-\frac12mu^2cos^2\theta\) |
| 3. | \(-\frac12mu^2sin^2\theta\) | 4. | \(-\frac12mu^2\) |
Subtopic: Â Work done by constant force |
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A force of \(100\) N acts on a block, always acting opposite to its velocity. The block moves from \(x=4\) m to \(x=10\) m and then to \(x=6\) m. The work done by the force is:
1. \(200\) J
2. \(-200\) J
3. \(1000\) J
4. \(-1000\) J
1. \(200\) J
2. \(-200\) J
3. \(1000\) J
4. \(-1000\) J
Subtopic: Â Work done by constant force |
From NCERT
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