| Column I | Column II | ||
| \(\mathrm{(A)}\) | Work done by force \(F\) on \(2~\text{kg}\) block | \(\mathrm{(I)}\) | \(20\sqrt2\) |
| \(\mathrm{(B)}\) | Work done by tension \((T)\) on \(2~\text{kg}\) block | \(\mathrm{(II)}\) | \(12\) |
| \(\mathrm{(C)}\) | Power due to force \(F,\) finally | \(\mathrm{(III)}\) | \(20\) |
| \(\mathrm{(D)}\) | Final kinetic energy of \(3~\text{kg}\) block | \(\mathrm{(IV)}\) | \(-12\) |
| 1. | A-II, B-II, C-III, D-I |
| 2. | A-III, B-IV, C-I, D-II |
| 3. | A-I, B-IV, C-III, D-II |
| 4. | A-II, B-IV, C-I, D-III |
| 1. | \(800\) | 2. | \(200\) |
| 3. | \(600\) | 4. | \(400\) |
1. at the instant just before the body hits the earth.
2. it remains constant all throughout.
3. at the instant just after the body is projected.
4. at the highest position of the body.
A motor pulls a block by giving a force of \(50\text{ N}\) at a speed of \(36\text{ km/h}.\) The power supplied by the motor to the block is:
1. \(500\text{ watt}\)
2. \(1800\text{ watt}\)
3. \(250\text{ watt}\)
4. \(200\text{ watt}\)
A truck of mass \(M\) accelerates from rest while the engine supplies a constant power \(P.\) The velocity attained after time \(t\) is proportional to:
1. \(t^{1/2}\)
2. \(t^{5/2}\)
3. \(t^{-1/2}\)
4. \(t^2\)
| 1. | \(\left(2 t^2+4 t^4\right)\text W\) | 2. | \(\left(2 t^3+3 t^3\right) \text W \) |
| 3. | \(\left(2 t^3+3 t^5\right) \text W\) | 4. | \(\left(2 t^3+3 t^4\right) \text W\) |
The force acting on a particle moving in a straight line is given by:
\(\vec{F}=(6 t^2 \hat{i}-3 t \hat{j})\) and its velocity at any instant is \(\vec{v}=(3 t^2 \hat{i}+6 t \hat{j}).\) Then, the instantaneous power delivered by the force at \( t = 2 ~\text s\) is:
| 1. | \(216 ~\text W\) | 2. | \(108 ~\text W\) |
| 3. | \(0 ~\text W\) | 4. | \(54~\text W\) |