A box of mass \(15\) kg is kept on the floor of a stationary trolley. The coefficient of static friction between the box and the trolley is \(0.12\cdot\) Keeping the box in a stationary state over the trolley; the maximum acceleration with which the trolley can be moved horizontally in \(\text{ms}^{-2}\) is: (\(g=10\) \(\text{ms}^{-2}\))
1. \(1.5\)
2. \(1.8\)
3. \(2.1\)
4. \(1.2\)
Subtopic:  Friction |
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Level 2: 60%+
NEET - 2026
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There are two inclined surfaces of equal length \((L)\) and same angle of inclination \(45^\circ\) with the horizontal. One of them is rough and the other is perfectly smooth. A given body takes \(2\) times as much time to slide down on rough surface than on the smooth surface. The coefficient of kinetic friction \((\mu_k)\) between the object and the rough surface is close to:
1. \(0.5\) 2. \(0.75\)
3. \(0.25\) 4. \(0.40\)
Subtopic:  Friction |
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Level 3: 35%-60%
NEET - 2025
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Calculate the maximum acceleration of a moving car so that a body lying on the floor of the car remains stationary. The coefficient of static friction between the body and the floor is \(0.15\). (take \(g=10\) ms–2)
1. \(50\) ms–2 2. \(1.2\) ms–2
3. \(150\) ms–2 4. \(1.5\) ms–2
Subtopic:  Friction |
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Level 1: 80%+
NEET - 2023
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A block of mass \(2\) kg is placed on inclined rough surface \(AC\) (as shown in the figure) of coefficient of friction \(\mu.\) If \(g=10\) ms–1, the net force (in N) on the block will be:
                    
1. \(10\sqrt3\)
2. zero
3. \(10\)
4. \(20\)
Subtopic:  Friction |
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Level 2: 60%+
NEET - 2023
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Calculate the acceleration of the block and trolly system shown in the figure. The coefficient of kinetic friction between the trolly and the surface is \(0.05.\) 
\(g=10~\text{m/s}^2,\) the mass of the string is negligible and no other friction exists)

1. \( 1.25~\text{m/s}^2\) 2. \( 1.50~\text{m/s}^2\)
3. \(1.66~\text{m/s}^2\) 4. \( 1.00~\text{m/s}^2\)
Subtopic:  Friction |
 67%
Level 2: 60%+
NEET - 2020
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A body of mass \(m\) is kept on a rough horizontal surface (coefficient of friction = \(\mu).\) A horizontal force is applied to the body, but it does not move. The resultant of normal reaction and the frictional force acting on the object is given by \(\vec {F}\) where:
1. \(|{\vec {F}}| = mg+\mu mg\)
2. \(|\vec {F}| =\mu mg\)
3. \(|\vec {F}| \le mg\sqrt{1+\mu^2}\)
4. \(|\vec{F}| = mg\)

Subtopic:  Friction |
 75%
Level 2: 60%+
NEET - 2019
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