A screw gauge has the least count of \(0.01~\text{mm}\) and there are \(50\) divisions in its circular scale. The pitch of the screw gauge is:
1. | \(0.25\) mm | 2. | \(0.5\) mm |
3. | \(1.0\) mm | 4. | \(0.01\) mm |
1. | \(9.98\) m | 2. | \(9.980\) m |
3. | \(9.9\) m | 4. | \(9.9801\) m |
If \(x=10.0\pm0.1\) and \(y=10\pm0.1\), then \(2x-2y\) with consideration of significant figures is equal to:
1. | zero | 2. | \(0.0\pm0.1\) |
3. | \(0.0\pm0.2\) | 4. | \(0.0\pm0.4\) |
The number of significant figures in \(0.0006032\) m2 is:
1. | \(4 \) | 2. | \(5\) |
3. | \(7\) | 4. | \(3\) |
If \({x}=\frac{{a} \sin \theta+{b} \cos \theta}{{a}+{b}},\) then:
1. | the dimensions of \(x\) and \(a\) must be the same |
2. | the dimensions of \(a\) and \(b\) are not the same |
3. | \(x\) is dimensionless |
4. | none of the above |
A thin wire has a length of \(21.7~\text{cm}\) and a radius of \(0.46~\text{mm}\). The volume of the wire to correct significant figures is:
1. | \( 0.15~ \text{cm}^3 \) | 2. | \( 0.1443~ \text{cm}^3 \) |
3. | \( 0.14~ \text{cm}^3 \) | 4. | \( 0.144 ~\text{cm}^3\) |
In an experiment, the height of an object measured by a vernier callipers having least count of \(0.01~\text{cm}\) is found to be \(5.72~\text{cm}\). When no object is there between jaws of this vernier callipers, the reading of the main scale is \(0.1\) cm and the reading of the vernier scale is \(0.3~\text{mm}\). The correct height of the object is:
1. \( 5.72 ~\text{cm} \)
2. \( 5.59~\text{cm} \)
3. \( 5.85~\text{cm} \)
4. \( 5.69~\text{cm} \)
In which of the following, the number of significant figures is different from that in the others?
1. | \(2.303~\text{kg}\) | 2. | \(12.23~\text{m}\) |
3. | \(0.002\times10^{5}~\text{m}\) | 4. | \(2.001\times10^{-3}~\text{kg}\) |
Which of the following relations is dimensionally wrong? [The symbols have their usual meanings]
1. \(s= ut+\frac{1}{6}at^2\)
2. \(v^2= u^2+\frac{2as^2}{\pi}\)
3. \(v= u-2at\)
4. All of these
When units of mass, length, and time are taken as \(10~\text{kg}, 60~\text{m}~\text{and}~60~\text{s}\) respectively, the new unit of energy becomes \(x\) times the initial SI unit of energy. The value of \(x\) will be:
1. \(10\)
2. \(20\)
3. \(60\)
4. \(120\)