What is the alteration in the oxidation state of carbon in the given reaction?
\(\mathrm{{CH_4}_{(g)} + 4{Cl_2}_{(g)} \rightarrow {CCl_4}_{(l)} + 4 HCl_{(g)}}\)
1. | 0 to +4 | 2. | –4 to +4 |
3. | 0 to –4 | 4. | +4 to +4 |
The incorrect oxidation number of the underlined atom in the following species is:
1. | Cu2O is -1 | 2. | Cl\(O_{3}^{-}\) is +5 |
3. | K2Cr2O7 is +6 | 4. | HAuCl4 is +3 |
The oxidation state of Cr in is -
1. | –6 | 2. | +12 |
3. | +6 | 4. | +4 |
The correct order of N-compounds in its decreasing order of oxidation states is :
1.
2.
3.
4.
(a) H2O2 + O3 → H2O + 2O2
(b) H2O2 + Ag2O → 2Ag + H2O + O2
The role of hydrogen peroxide in the above reactions is respectively:
1. | Oxidizing in (a) and reducing in (b) |
2. | Reducing in (a) and oxidizing in (b) |
3. | Reducing in (a) and (b) |
4. | Oxidizing in (a) and (b) |
The change in oxidation number of chlorine when Cl2 gas reacts with hot and concentrated sodium hydroxide solution is:
1. Zero to +1 and Zero to –5
2. Zero to –1 and Zero to +5
3. Zero to –1 and Zero to +3
4. Zero to +1 and Zero to –3
The highest oxidation number of nitrogen among the following compounds is:
1. | 2. | ||
3. | 4. |
Oxidation numbers of P in , of S in and that of Cr in are respectively:
1. +5, +6 and +6
2. +3, +6 and +5
3. +5, +3 and +6
4. -3, +6 and +6
The oxidation states(O.S.) of sulphur in the anions follow the order:
1.
2.
3.
4.
If the oxidation numbers of A, B, and C are + 2, +5, and –2 respectively, then the possible formula of the compound is:
1. | A2(BC2)2 | 2. | A3(BC4)2 |
3. | A2(BC3)2 | 4. | A3(B2C)2 |