Q. No.
The major product of Williamson’s ether synthesis reaction would be:
| 1. | Benzene | 2. | Methoxy benzene |
| 3. | Ethoxy benzene | 4. | Ethane |
In the following Williamson’s synthesis reaction,
CH3CH2ONa + CH3-Br → ?
The product will be:
| 1. | 1-Methoxyethane | 2. | 2-Methoxyethane |
| 3. | 3-Methoxyethane | 4. | 4-Methoxyethane |
Match the following:
| List I | List II | ||
| i. | O2N-C6H5-OCH3 (p) | a. | 4-Ethoxy-1,1-dimethylcyclohexane |
| ii. | C2H5OCH2-CH(CH3)2 | b. | 1-Chloro-2-methoxyethane |
| iii. | CH3OCH2CH2Cl | c. | 1-Ethoxy-2-methylpropane |
| iv. |  |
d. | 1-Methoxy-4-nitrobenzene |
| i | ii | iii | iv | |
| 1. | d | c | b | a |
| 2. | c | d | b | a |
| 3. | a | c | b | d |
| 4. | b | c | d | a |
What is the product of the reaction of hydrogen iodide with benzyl ethyl ether?
1. Ethanol
2. Benzyl iodide
3. Benzyl iodide and Ethanol
4. None of the above
The reaction of 3-methylbutan-2-ol with HBr gives:
| 1. | 2-Bromo-3-methyl butane | 2. | 2-Bromo-2-methyl butane |
| 3. | 3-Bromo-2-methyl butane | 4. | 3-Bromo-3-methyl butane |
The proposed mechanism for hydration of ethene to yield ethanol is as follows:
The wrong step in the above mechanism is:
| 1. | Step 1 | 2. | Step 2 |
| 3. | Step 3 | 4. | Both steps 2 and 3 |
"A" in the reaction below is:
| 1. | Chlorobenzene | 2. | 1,2-Dichlorobenzene |
| 3. | 1,3-dichlorobenzene | 4. | None of these |
The IUPAC name of the below compound is:
1. 3,4-Dimethylhexane –1,3,5-triol
2. 3,5-Dimethylhexane –1,1,5-triol
3. 3,5-Dimethylhexane –1,3,5-triol
4. 3,1-Dimethylhexane –1,3,5-triol
The IUPAC name of the below compound is:
| 1. | 1-Phenylpropan-2-ol | 2. | 2-Phenylpropan-2-ol |
| 3. | 1-Phenylpropan-1-ol | 4. | 2-Phenylpropan-1-ol |
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