If the velocity of a particle is given by \(v = (180-16x)^{1/2}~\text{m/s}\), then its acceleration will be:
1. | zero | 2. | \(8\) m/s2 |
3. | \(-8\) m/s2 | 4. | \(4\) m/s2 |
A body is thrown vertically upwards. If the air resistance is to be taken into account, then the time during which the body rises is:
1. | Equal to the time of fall. |
2. | Less than the time of fall. |
3. | Greater than the time of fall. |
4. | Twice the time of fall. |
A body starts to fall freely under gravity. The distances covered by it in the first, second and third second will be in the ratio:
1. | \(1:3:5\) | 2. | \(1:2:3\) |
3. | \(1:4:9\) | 4. | \(1:5:6\) |
A body is thrown vertically up from the ground. It reaches a maximum height of \(100\) m in \(5\) s. After what time will it reach the ground from the position of maximum height?
1. | \(1.2\) s | 2. | \(5\) s |
3. | \(10\) s | 4. | \(25\) s |
If a body is thrown up with the velocity of \(15\) m/s, then the maximum height attained by the body is: (assume \(g = 10\) m/s2)
1. \(11.25\) m
2. \(16.2\) m
3. \(24.5\) m
4. \(7.62\) m
If a freely falling body travels in the last second a distance equal to the distance travelled by it in the first three seconds, the time of the travel is:
1. \(6\) sec
2. \(5\) sec
3. \(4\) sec
4. \(3\) sec
A particle moving in a straight line covers half the distance with a speed of \(3~\text{m/s}\). The other half of the distance is covered in two equal time intervals with speeds of \(4.5~\text{m/s}\) and \(7.5~\text{m/s}\) respectively. The average speed of the particle during this motion is:
1. \(4.0~\text{m/s}\)
2. \(5.0~\text{m/s}\)
3. \(5.5~\text{m/s}\)
4. \(4.8~\text{m/s}\)
A particle starts from rest. Its acceleration \((a)\) versus time \((t)\) is as shown in the figure. The maximum speed of the particle will be:
1. \(110~\text{m/s}\)
2. \(55~\text{m/s}\)
3. \(550~\text{m/s}\)
4. \(660~\text{m/s}\)
A stone dropped from a building of height \(h\) and reaches the earth after \(t\) seconds. From the same building, if two stones are thrown (one upwards and other downwards) with the same velocity \(u\) and they reach the earth surface after \(t_1\) and \(t_2\) seconds respectively, then:
1.
2.
3.
4.
A particle is dropped vertically from rest from a height. The time taken by it to fall through successive distances of \(1~\text{m}\) each will then be:
1. | \(\sqrt{2 / g} \) s. | All equal, being equal to
2. | In the ratio of the square roots of the integers \(1,2,3....\) |
3. | \(\sqrt{1}\), \((\sqrt{2}-\sqrt{1})\),\((\sqrt{3}-\sqrt{2})\),\((\sqrt{4}-\sqrt{3})\) \( \ldots\) | In the ratio of the difference in the square roots of the integers
4. | \(\frac{1}{\sqrt{1}}\), \(\frac{1}{\sqrt{2}}\), \(\frac{1}{\sqrt{3}}\),\(\frac{1}{\sqrt{4}} \) | In the ratio of the reciprocal of the square roots of the integers i.e,...