Among Group 16 elements, which one does NOT show -2 oxidation state?

1. Se
2. Te
3. Po
4. O
Subtopic:  Group 16 - Preparation, Properties & Uses |
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From NCERT
NEET - 2024
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Given below are two statements :
Statement I : The boiling point of hydrides of Group 16 elements follow the order 
\(\text{H}_2 \text{O}>\text{H}_2 \text{Te}>\text{H}_2 \text{Se}>\text{H}_2 \text{S} .\)
Statement II : On the basis of molecular mass, H2O is expected to have lower boiling point than the other members of the group but due to the presence of extensive H-bonding in H2O, it has higher boiling point. 

In the light of the above statements, choose the correct answer from the options given below:

1. Both statement I and statement II are false.
2. Statement I is true and Statement II is false
3. Statement I is false but Statement II is true.
4. Both Statement I and Statement II are true.
Subtopic:  Group 16 - Preparation, Properties & Uses |
 78%
From NCERT
NEET - 2024
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The products A and B obtained in the following reactions, respectively, are 
\( \begin{aligned} & 3 \mathrm{ROH}+\mathrm{PCl}_3 \rightarrow 3 \mathrm{RCl}+\mathrm{A} \\ & \mathrm{ROH}+\mathrm{PCl}_5 \rightarrow \mathrm{RCl}+\mathrm{HCl}+\mathrm{B} \end{aligned} \)

1. \(\mathrm{POCl}_3~ and~ \mathrm{H}_3 \mathrm{PO}_4 \)
2. \(\mathrm{H}_3 \mathrm{PO}_4~ and ~\mathrm{POCl}_3 \)
3. \(\mathrm{H}_3 \mathrm{PO}_3~and ~\mathrm{POCl}_3 \)
4. \(\mathrm{POCl}_3~and ~\mathrm{H}_3 \mathrm{PO}_3\)
Subtopic:  Group 15 - Preparation, Properties & Uses |
 71%
From NCERT
NEET - 2024
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Match the Oxoacids of Sulphur given in List I with the number of bond given in List II and mark the correct option.
List-I
(Oxoacids of Sulphur)
List-II
(Bonds)
A.  Peroxodisulphuric acid I. Two S-OH, Four S=O, One S-O-S
B. Sulphuric acid II. Two S-OH, One S=O
C. Pyrosulphuric acid III. Two S-OH, Four S=O, One S-O-O-S
D.  Sulphurous acid IV.  Two S-OH, Two S=O
Choose the correct answer from the options given below: 
Options: A B C D
1. III IV II I
2. I III II IV
3. III IV I II
4. I III IV II
Subtopic:  Group 16 - Preparation, Properties & Uses |
 70%
From NCERT
NEET - 2023
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Select the correct option based on the statements below:
 
Assertion (A): ICl is more reactive than I₂.
Reason (R): I-Cl bond is weaker than I-I bond.
 
1. (A) is False but (R) is True.
2. Both (A) and (R) are True and (R) is the correct explanation of (A).
3. Both (A) and (R) are True but (R) is not the correct explanation of (A).
4. (A) is True but (R) is False.
Subtopic:  Group 17 - Preparation, Properties & Uses |
 75%
From NCERT
NEET - 2022
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Given below are two statements:
Statement I: The boiling points of the following hydrides of group 16 elements increase in the order 
\(\mathrm{H}_{2} \mathrm{O}<\mathrm{H}_{2} \mathrm{~S}<\mathrm{H}_{2} \mathrm{Se}<\mathrm{H}_{2} \mathrm{Te} \)  
Statement II: The boiling points of these hydrides increase with the increase in molar mass.
In the light of the above statements, choose the most appropriate answer from the options given below:
1. Statement I is incorrect but Statement II is correct 
2. Both Statement I and Statement II are correct 
3. Both Statement I and Statement II are incorrect 
4. Statement I is correct but Statement II is incorrect
Subtopic:  Group 16 - Preparation, Properties & Uses |
From NCERT
NEET - 2022
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The correct order for boiling points of the following compounds is: 

1. AsH3 > PH3 > NH3 > SbH3 > BiH3
2. BiH3 > SbH3 > NH3 > AsH3 > PH3
3. NH3 > PH3 > AsH3 > SbH3 > BiH3
4. PH3 > NH3 > AsH3 > SbH3 > BiH3
Subtopic:  Group 15 - Preparation, Properties & Uses |
 63%
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NEET - 2022
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Chlorine shows the bleaching action in the presence of moisture due to the formation of 
1. HOCl 
2. HOClO
3. H2O2
4. O

Subtopic:  Group 17 - Preparation, Properties & Uses |
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NEET - 2022
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The reaction that is a part of large scale industrial preparation of nitric acid is: 
1. \(\mathrm{NaNO}_3+\mathrm{H}_2 \mathrm{SO}_4\xrightarrow[500~K, \ 9\text{ bar}]{Pt} \mathrm{NaHSO}_4+\mathrm{HNO}_3\)
2. \(4 \mathrm{NH}_3+5 \mathrm{O}_2 \text{(from air)}\xrightarrow[500~K, \ 9\text{ bar}]{Pt} 4 \mathrm{NO}+6 \mathrm{H}_2 \mathrm{O}\)
3. \(4 \mathrm{HPO}_3+2 \mathrm{~N}_2 \mathrm{O}_5\xrightarrow[500~K, \ 9\text{ bar}]{Pt} 4 \mathrm{HNO}_3+\mathrm{P}_4 \mathrm{O}_{10}\)
4. \(\mathrm{Cu}\left(\mathrm{NO}_3\right)_2+2 \mathrm{NO}_2+2 \mathrm{H}_2 \mathrm{O} \\ \xrightarrow[500~K, \ 9\text{ bar}]{Pt} 4 \mathrm{HNO}_3+\mathrm{Cu}\)
Subtopic:  Group 15 - Preparation, Properties & Uses |
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NEET - 2022
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Fluorine is a stronger oxidizing agent than chlorine because:
(a) F–F bond has a low enthalpy of dissociation.
(b) Flouride ion (F) has high hydration enthalpy.
(c) Electron gain enthalpy of fluorine is less negative than chlorine.
(d) Fluorine has a very small size.
Choose the most appropriate answer from the options given :
1. (a) and (b) only 2. (a) and (c) only
3. (a) and (d) only 4. (b) and (c) only
Subtopic:  Group 17 - Preparation, Properties & Uses |
From NCERT
NEET - 2022
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