The correct hybridization states of carbon atoms in the following compound are - $\stackrel{1}{\mathrm{\hspace{0.17em}\; \hspace{0.17em}\; C}}{H}_2=\stackrel{2}{C}H-\stackrel{3}{C}\equiv N$
 

The number of σ and π bonds in the molecule ${\mathrm{CH}}_2{\mathrm{Cl}}_2$ are -

1.  2 = (${\sigma }_{C-Cl})$ , 1= $\left({\sigma }_{C-H}\right)$ , and 1= π

2. 2 = (${\sigma }_{C-Cl})$ , 2= $\left({\sigma }_{C-H}\right)$ , and 0= π

3. 2 = (${\sigma }_{C-Cl})$ , 1= $\left({\sigma }_{C-H}\right)$ , and 1= π

4. 2 = (${\sigma }_{C-Cl})$ , 1= $\left({\sigma }_{C-H}\right)$ , and 1= π

$\stackrel{1}{C}{H}_2$ $=\stackrel{2}{C}=O$

The correct hybridization states of carbon atoms in the above compound are - 

The correct hybridization states of carbon atoms marked as 1,2,3 in the following compound are:
\({ }^1 \mathrm{CH}_3-\mathrm{ }^2{C} \mathrm{H}={}^3{\mathrm{C}} \mathrm{H}_2 \)

The number of σ and π bonds in the molecule $C_6{H}_6$ are -

The number of primary carbon atoms in the following compound are:

The enolic form of ethyl acetoacetate is given below. The number of sigma and pi bonds in the enolic form of ethyl acetoacetate are:

1. 18 sigma bonds and 2 pi-bonds

2. 16 sigma bonds and 1 pi-bond

3. 9 sigma bonds and 2 pi-bonds

4. 9 sigma bonds and 1 pi-bond

The correct hybridization states of carbon atoms in C₆H_{6 (cyclic compound)} is/are:

1.  sp² 

2. sp

3. sp³

4.  All of the above

The cylindrical shape of an alkyne is due to the presence of- 

1. Three sigma C-C bonds

2. Three π C-C bonds

3. Two sigma C-C and one π C-C bonds

4. One sigma C-C and two π C-C bonds

The \(C - H\) bond distance is longer in -