The molar solubility of ${\mathrm{CaF}}_2$ $({\mathrm{K}}_{\mathrm{sp}}=5.3$ $\mathrm{\times }$ ${10}^{-11})$ in 0.1 M solution of NaF will be:

1.	$5.3$ $\mathrm{\times }$ ${10}^{-11}$ $\mathrm{mol}$ ${\mathrm{L}}^{-1}$	2.	$5.3$ $\mathrm{\times }$ ${10}^{-8}$ $\mathrm{mol}$ ${\mathrm{L}}^{-1}$
3.	$5.3$ $\mathrm{\times }$ ${10}^{-9}$ $\mathrm{mol}$ ${\mathrm{L}}^{-1}$	4.	$5.3$ $\mathrm{\times }$ ${10}^{-10}$ $\mathrm{mol}$ ${\mathrm{L}}^{-1}$

Which of the following cannot act both as a Bronsted acid and as a Bronsted base?

1. \(\mathrm{H C O_{3}^{-}}\)

2. \(\mathrm{NH_3}\)

3. \(\mathrm{HCl}\)

4. \(\mathrm{H S O_{4}^{-}}\)

1. H₃O⁺ and H₂F⁺, respectively.

2. OH^– and H₂F⁺, respectively.

3. H₃O⁺ and F^–, respectively.

4. OH^– and F^–, respectively.

pH of a saturated solution of \(Ca \left(OH\right)_{2}\) is 9. The solubility product \(K_{sp}\) of \(Ca \left(OH\right)_{2}\) is:
1. \(0 . 5 \times \left(10\right)^{- 10}\)
2. \(0 . 5 \times \left(10\right)^{- 15}\)
3. \(0 . 25 \times \left(10\right)^{- 10}\)
4. \(0 . 125 \times \left(10\right)^{- 15}\)

Which composition will make the basic buffer?

Given that the ionic product of $\mathrm{Ni}{\left(\mathrm{OH}\right)}_2$ is 2 × ${10}^{-\mathrm{15 }}$. The solubility of $\mathrm{Ni}{\left(\mathrm{OH}\right)}_2$ in 0.1 M NaOH is ;
1. 2 × ${10}^{-8}$ M

The salt solution that is basic in nature is: 

1. Ammonium chloride.

2. Ammonium sulphate.

3. Ammonium nitrate.

4. Sodium acetate.

The solubility product for a salt of type AB is $4\times {10}^{-8}$.  The molarity of its standard solution will be:
1. $2\times {10}^{-4}$ $\mathrm{mol}/\mathrm{L}$

2. $16\times {10}^{-16}$ $\mathrm{mol}/\mathrm{L}$

3. $2\times {10}^{-16}$ $\mathrm{mol}/\mathrm{L}$

4. $4\times {10}^{-4}$ $\mathrm{mol}/\mathrm{L}$

The pK_b of dimethylamine and pk_a of acetic acid are 3.27 and 4.77 respectively at T (K).
The correct option for the pH of dimethylammonium acetate solution is: