Match the compounds given in Column-I with their respective hybridisation which is  given in Column-II.
Column-I (Compound) Column-II Hybridisation
(i) \(PCl_5 \) (a) \(sp^3d^2 \)
(ii) \([Pt(CN)_4]^{-2} \) (b) \(sp^3d \)
(iii) \([Co(NH_3)_6]^{3+} \) (c) \(d^2sp^3 \)
(iv) \(BrF_5 \) (d) \(dsp^2 \)
Correct matching is: 
I II III IV
1. b d c a
2. a b c d
3. b d a c
4. d b a c
Subtopic:  Hybridisation | V.S.E.P.R & V.B.T |
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Identify the correct statement regarding SF4
 
1. It has one lone pair at the equatorial position with two lone pair-bond pair repulsion at 90°.
2. It has one lone pair at the axial position with two lone pair-bond pair repulsion at 90°.
3. It has one lone pair at the equatorial position with three lone pair-bond pair repulsion at 90°.
4. It has one lone pair at the axial position with three lone pair-bond pair repulsion at 90°.
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In C1H2=C2=C3HC4H3 molecule, the hybridization of carbon 1,2,3 and 4 respectively are :

1. sp3,sp,sp3,sp3

2. sp2,sp2,sp2,sp3

3. sp2,sp,sp2,sp3

4. sp2,sp3,sp2,sp3

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The molecule in which hybrid MOs involve only one d-orbital of the central atom is:

1. \(X e F_{4}\)

2. \(\left[ N i (CN)_{4} \right]^{2 -}\)

3. \(B r F_{5}\)

4. \(\left[ C r F_{6} \right]^{3 -}\)

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The structure of PCl5 in the solid state is: 

1. Square pyramidal.
2. Tetrahedral [PCl4]and octahedral [PCl6]
3. Square planar [PCl4] and octahedral [PCl6]
4. Trigonal bipyramidal.

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The compound that has the largest H–M–H bond angle (M=N, O, S, C), is:

1. H2O 2. CH4
3. NH3 4. H2S
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The ion that has sp3d2 hybridization for the central atom is:

1. [ICl4]

2. [ICl2]

3. [BrF2]

4. [IF6]

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Total number of lone pair of electrons in \({I }_{3}^{-}\) ion are:

1. 3 2. 6
3. 9 4. 12
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In which of the following pairs the two species are not isostructural?

1. PCl4+ and SiCl4

2. PF5  and BrF5

3. AlF63− and SF6

4. CO32− and NO3

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Which of the following compounds has the smallest bond angle?

1. SO

2. H2

3. H2

4. NH

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