- 1(current)
Q. No.The kinetic energy of a particle continuously increases with time. It follows that:
| 1. | its potential energy must decrease with time |
| 2. | the net force acting on it cannot be perpendicular to its path |
| 3. | the net force acting on it is along the velocity |
| 4. | friction cannot act on it |
Subtopic: Â Work Energy Theorem |
Level 3: 35%-60%
Please attempt this question first.
Hints
Please attempt this question first.
Given below are two statements:
| Assertion (A): | The net work done by gravity is equal to the loss in the vertical component of the kinetic energy for a projectile. |
| Reason (R): | The work-energy theorem applies to all systems including projectiles. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | (A) is False but (R) is True. |
Subtopic: Â Work Energy Theorem |
Level 3: 35%-60%
Hints
A projectile is launched from a cliff of height \(h,\) with an initial speed \(u,\) at an angle \(\theta.\) The speed with which it hits the ground:
| 1. | depends on the vertical component, \(u \text{sin}\theta\) |
| 2. | depends on the horizontal component, \(u \text{cos}\theta\) |
| 3. | depends on \(u,\) but not on \(\theta\) |
| 4. | depends on the quantity \(u \text{tan}\theta\) |
Subtopic: Â Work Energy Theorem |
Level 3: 35%-60%
Hints
When a fan is switched on and it begins to rotate:
| 1. | Its K.E. increases |
| 2. | Work is done by centrifugal force |
| 3. | Work is done by centripetal forces |
| 4. | Mechanical forces do not do any work |
Subtopic: Â Work Energy Theorem |
 52%
Level 3: 35%-60%
Please attempt this question first.
Hints
Please attempt this question first.
A particle of mass '\(m\)' is released from the origin, and it moves under the action of a force: \(F(x)= F_0-kx\)
The maximum speed of the particle is, \(v= \)
| 1. | \(\sqrt{\dfrac{F_0^2}{mk}}\) | 2. | \(\sqrt{\dfrac{2F_0^2}{mk}}\) |
| 3. | \(\sqrt{\dfrac{F_0^2}{2mk}}\) | 4. | \(2\sqrt{\dfrac{F_0^2}{mk}}\) |
Subtopic: Â Work Energy Theorem |
 51%
Level 3: 35%-60%
Hints
- 1(current)
Q. No.
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