It is known that an atom contains protons, neutrons, and electrons. If the mass of the neutron is assumed to be half of its original value, and that of the proton is assumed to be twice its original value, then the atomic mass of ${}_6{}^{14}\mathrm{C}$ will:

1.	Remain the same	2.	be 14.28% less
3.	be 14.28% more	4.	be 28.56% less

Nitric acid can be produced ${\mathrm{NH}}_3$ in three steps process

(I) $4N{H}_3\left(g\right) + 5O_2\left(g\right)\to 4NO\left(g\right) + 6H_{2}O\left(g\right)$
(II) $2NO\left(g\right) + O_2\left(g\right)\to 2N{O}_2\left(g\right)$
(III) $3N{O}_2\left(g\right) + H_{2}O\left(l\right) \to 2HN{O}_3\left(aq\right) + NO\left(g\right)$

percent yield Ist, IInd and IIIrd are respectively 50%, 60% and 80% respectively then what volume of $N{H}_3\left(g\right)$ at 1 atm and 0$°$C required to produces 1575 g of $HN{O}_3$

1. 156.25

2. 350 L

3. 3500 L

4. None of these

A gaseous mixture of ${\mathrm{H}}_2$ and ${\mathrm{CO}}_2$ gas contains 66 mass % of ${\mathrm{CO}}_2$. The vapour density of the mixture is:

1.  6.1

2.  5.4

3.  2.7

4.  10.8

How much volume of 75% alcohol by weight (d=0.80 g/cm³) is required to prepare 150 cm³ of 30% alcohol by weight (density = 0.90 g/cm³)?

The average atomic mass of magnesium is 24.31 a.m.u. Magnesium consists of three isotopes: \(^{24}Mg\), \(^{25}Mg \), and \(^{26}Mg\). The mole percentage of \(^{24}Mg\) is 79%, and the remaining 21% is a mixture of \(^{25}Mg \) and \(^{26}Mg\).
Calculate the mole percentage of \(^{26}Mg\).

1.  10 %
2.  11 %
3.  15 %
4.  16 %

A mixture of ${\mathrm{O}}_2$ and gas "Y" (mol. wt. 80) in the mole ratio a : b has a mean molecular weight of 40. What would be the mean molecular weight, if the gases are mixed in the ratio b : a under identical conditions? (assume that these gases do not react)

 If 2.74 g of the metal oxide contains 1.53 g of metal, then the empirical formula of vanadium oxide is:

(Atomic Mass of V = 52)

1. ${\mathrm{V}}_2{\mathrm{O}}_3$

2. $\mathrm{VO}$

3. ${\mathrm{V}}_2{\mathrm{O}}_5$

4. ${\mathrm{V}}_2{\mathrm{O}}_7$

A gaseous mixture of propane and butane of volume 3 litre on complete combustion produces 11.0 litre $C{O}_2$ under standard conditions of temperature and pressure. The ratio of volume of butane to propane is:

1. 1 : 2

2. 2 : 1

3. 3 : 2

4. 3 : 1

The percentage by volume of $C_3{H}_8$ in a gaseous mixture of $C_3{H}_8$, $C{H}_4$ and CO is 20. When 100 mL of the mixture is burnt in excess of $O_2$, the volume of $C{O}_2$ produced is:

1. 90 mL

2. 160 mL

3. 140 mL

4. None of the above

The percentage of oxygen present in the compound ${\mathrm{CaCO}}_3.3{\mathrm{Ca}}_3 {\left({\mathrm{PO}}_4\right)}_2$ is-

1.  23.3%

2.  45.36%

3.  41.94%

4.  17.08%