Which of the following represents the correct order of reducing power of metals X, Y, and Z having standard electrode potentials −1.2 V, +0.5 V, and −3.0 V, respectively?
 
1. Y > X > Z 2. Z > X > Y
3. X > Y > Z 4. Y > Z > X

Subtopic:  Electrode & Electrode Potential |
 81%
Level 1: 80%+
AIPMT - 2011
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If the  Ecell 0for a given reaction has a negative value, then which of the following gives the correct relationship for the values of ∆G0  and   Keq?

1.  ∆G0<0; Keq>1

2.  ∆G0<0; Keq<1

3.  ∆G0>0; Keq<1

4.  ∆G0>0; Keq>1

Subtopic:  Electrolytic & Electrochemical Cell | Relation between Emf, G, Kc & pH |
 81%
Level 1: 80%+
AIPMT - 2011
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Based on electrode potentials in the table below: 
Cu2+(aq) + e- → Cu+(aq) 0.15 V
Cu+(aq) + e- → Cu(s) 0.50 V

The value of \(E_{Cu^{2+}/Cu}^{o}\) will be:
1. 0.325 V 2. 0650 V
3. 0.150 V 4. 0.500 V
Subtopic:  Electrode & Electrode Potential |
 63%
Level 2: 60%+
AIPMT - 2011
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What is the standard cell potential when the Sn⁴⁺/Sn²⁺ (E° = +0.15 V) and Cr³⁺/Cr (E° = −0.74 V) half-cells are connected under standard conditions?

1. +0.89 V

2. +0.18 V

3. +1.83 V

4. +1.199 V

Subtopic:  Electrode & Electrode Potential |
 92%
Level 1: 80%+
AIPMT - 2011
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In producing chlorine by electrolysis, 100 kW power at 125 V is being consumed.
How much chlorine per minute is liberated:
(Given -ECE of chlorine is 0.367 X 10-6 kgC-1)

1.1.76×10-3 kg

2. 9.67×10-3 kg

3. 17.61×10-3 kg

4. 3.67×10-3 kg

Subtopic:  Faraday’s Law of Electrolysis |
 56%
Level 3: 35%-60%
AIPMT - 2010
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Find the standard Gibbs energy change for the reduction of Ag⁺ by copper metal if E°cell = +0.46 V at 25°C.

Given: F = 96,500 C mol⁻¹

1. -89.0 kJ

2. -89.0 J

3. -44.5 kJ

4. -98.0 kJ

Subtopic:  Faraday’s Law of Electrolysis |
 72%
Level 2: 60%+
AIPMT - 2010
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Al2O3 is reduced by electrolysis at low potentials and high currents. If 4.0 x 104 A of current is passed through molten Al2O3 for 6 hours, the mass of aluminum produced is:
(Assume 100 % current efficiency, the atomic mass of Al = 27 g mol-1)

1. 9.0 x 103 g 2. 8.1 x 104 g
3. 2.4 x 105 g 4. 1.3 x 104 g
Subtopic:  Faraday’s Law of Electrolysis |
 67%
Level 2: 60%+
AIPMT - 2009
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The molar conductance of M32 solution of a weak monobasic acid is 8.0 ohm-1 cm2 and at infinite dilution is 400 ohm-1 cm2. The dissociation constant of this acid is: 

1. \(1.25 \times10^{-5}\) 2. \(1.25 \times10^{-6}\)
3. \(6.25 \times10^{-4}\) 4. \(1.25 \times10^{-4}\)
Subtopic:   Kohlrausch Law & Cell Constant |
 66%
Level 2: 60%+
AIPMT - 2009
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Given:
(i) Cu2++2e-→Cu    Eo = 0.337 V 
(ii) Cu2++e-→Cu+  Eo = 0.153 V 
Electrode potential, Eo for the reaction, 
Cu++e-→Cu, will be: 

1. 0.52 V

2. 0.90 V

3. 0.30 V

4. 0.38 V

Subtopic:  Relation between Emf, G, Kc & pH |
 76%
Level 2: 60%+
AIPMT - 2009
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Kohlrausch's law states that at:

1. Finite dilution, each ion makes definite contribution to equivalent conductance of an electrolyte, whatever be the nature of the other ion of the electrolyte.
2. Infinite dilution, each molecule makes definite contribution to equivalent conductance of an electrolyte depending on the nature of the other ion of the electrolyte.
3. Finite dilution, each molecule makes definite contribution to conductance of an electrolyte whatever be the nature of the other ion of the electrolyte.
4. Infinite dilution, each ion makes definite contribution to equivalent conductance of an electrolyte, whatever be the nature of the other ion of the electrolyte.
Subtopic:   Kohlrausch Law & Cell Constant |
 61%
Level 2: 60%+
AIPMT - 2008
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