NEET Physics Mathematical Tools Questions Solved


Given the vectors

                         A=2i^+3j^-k^                         B=3i^-2j^-2k^&                      C=pi^+pj^+2pk^

Find the angle between A-B & C

(A)  θ=cos-123

(B)  θ=cos-132

(C)  θ=cos-123

(D)  none of these

Concept Videos :-

#25 | Vectors: Multiplication with Scalar
#26 | Vectors: Multiplication with Vector : Dot Product

Concept Questions :-

Scalar Product

(C)

 

A-B= 2i^+3j^-k^-3i^-2j^-2k^          = -i^+5j^+k^Let A-B= D   let D= -i^+5j^+k^     D= -12+52+12    = 27To find the angle between D & CC= p2+p2+2p2   = P6D. C= DC cosθ-i^+5j^+k^. pi^+pj^+2pk^= 27×p6 cosθ-p+5p+2p= p27×6 cosθ6= 27×6 cosθcosθ= 627         = 29cosθ= 23    or    θ=cos-123

Difficulty Level:

  • 17%
  • 11%
  • 53%
  • 21%
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