An organic compound A on reduction gives compound B which on reaction with chloroform and potassium hydroxide forms C. The compound C on catalytic reduction gives N-methylaniline. The compound A is                                                                                      [2000]

1. nitrobenzene

2. nitromethane

3. methylamine

4. aniline

An aromatic primary amine with cold nitrous acid leads to the formation of:

1. alcohol

2. nitrite

3. diazonium salt

4. benzene

X and Y in the given reaction are:

1. ${\mathrm{CH}}_3\mathrm{COOH}<mspace\; width="1em"></mspace>+<mspace\; width="1em"></mspace>({\mathrm{CH}}_3{)}_2\mathrm{NH}$

2. ${\mathrm{CH}}_3{\mathrm{CONH}}_2<mspace\; width="1em"></mspace>+<mspace\; width="1em"></mspace>{\mathrm{CH}}_3\mathrm{OH}$

3. ${\mathrm{CH}}_3\mathrm{CHO}<mspace\; width="1em"></mspace>+<mspace\; width="1em"></mspace>({\mathrm{CH}}_3{)}_2\mathrm{NH}$

4. ${\mathrm{CH}}_3{\mathrm{COCH}}_3<mspace\; width="1em"></mspace>+<mspace\; width="1em"></mspace>{\mathrm{CH}}_3{\mathrm{NH}}_2$

Which of the following statements about primary amines is false ?

[2010]

1. Alkyl amines are stronger bases than aryl amines

2. Alkyl amines react with nitrous acid to produce alcohols

3. Aryl amines react with nitrous acid to produce phenols

4. Alkyl amines are stronger bases than ammonia

Among the following, the strongest base is:

1. C₆H₅NH₂

2. p-NO₂-C₆H₄NH₂

3. m-NO₂-C₂H₄NH₂

4. C₂H5CH₂NH₂

Which of the following reactions does not yield an amine?

1.  

2.   

3.  

4.    ​​​​​​​

The end product in the following sequence of reactions is -

${\mathrm{C}}_2{\mathrm{H}}_5{\mathrm{NH}}_2\stackrel{{\mathrm{HNO}}_2}{\to }A<mspace\; width="1em"></mspace>\stackrel{{\mathrm{PCl}}_5}{\to }B\stackrel{{\mathrm{NH}}_3}{\to }C?$
$$

1. Ethyl cyanide

2. Ethylamine

3. Methylamine

4. Acetamide

Identfy X in the sequence,

$X<mspace\; width="1em"></mspace>\stackrel{{\mathrm{HNO}}_2}{\to }{\mathrm{C}}_3{\mathrm{H}}_8\mathrm{O}<mspace\; width="1em"></mspace>\underset{{\mathrm{H}}_2{\mathrm{SO}}_4}{\overset{{\mathrm{K}}_2{\mathrm{Cr}}_2{\mathrm{O}}_7}{\to }}{\mathrm{C}}_3{\mathrm{H}}_6{\mathrm{O}}_2$ :

1. ${\mathrm{CH}}_3-\mathrm{NH}-{\mathrm{CH}}_2-{\mathrm{CH}}_3$

2. ${\mathrm{CH}}_3-{\mathrm{CH}}_2-{\mathrm{CH}}_2-{\mathrm{NH}}_2$

3. $({\mathrm{CH}}_3{)}_3\mathrm{N}$

4. none of the above

CH₃CH₂NH₂ contains a basic NH₂ group, but CH₃CONH₂ does not, because;

1. acetamide is amphoteric in character

2. in CH₃CH₂NH₂ the electron pair on N-atom is delocalized by resonance

3. in CH₃CH₂NH₂ there is no resonance, while in acetamide the lone pair of electron on N-atom is delocalized and therefore less available for protonation

4. none of the above

Tertiary nitro compounds cannot show tautomerism because:

1. they are very stable

2. isomerises to give sec. nitro compounds

3. do not have labile H-atom

4. they are highly eactive