NEET Physics Nuclei Questions Solved


In the nuclear fusion reaction H12+H13He24+n given that the repulsive potential energy between the two nuclei is -7.7×10-14 J, the temperature at which the gases must be heated to initiate the reaction is nearly
[Boltzmann’s constant k=1.38×10-23 J/K)
(a)109 K            (b) 107 K
(c) 105 K           (d)  103 K

(a) Kinetic energy of the molecules of a gas at a temp. T is 32kT
 To initiate the reaction 32kT=7.7×10-14 J

32×1.38×10-23 T=7.7×10-14T=3.7×109 K
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