NEET Physics Nuclei Questions Solved


The rest energy of an electron is 0.511 MeV. The electron is accelerated from rest to a velocity 0.5 c. The change in its energy will be
(a) 0.026 MeV            (b) 0.051 MeV
(c) 0.079 MeV            (d) 0.105 MeV

(c) =mc2-m0c2=m0c21-v2/c2-m0c2

=m0c211-v2/c2-1=0.51110.75-1

= 0.079 MeV

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