NEET Physics Nuclei Questions Solved

The sun radiates energy in all directions. The average radiations received on the earth surface from the sun is 1.4 $\mathrm{kilowatt}/{\mathrm{m}}^{2}$.The average earth- sun distance is $1.5×{10}^{11}$ metres. The mass lost by the sun per day is
(1 day = 86400 seconds)
(a)           (b)
(c)          (d)

(d) Energy radiated = 1.4 $\mathrm{kW}/{\mathrm{m}}^{2}$

$=\frac{4\mathrm{\pi }×{\left(1.5×{10}^{11}\right)}^{2}×1.4×86400}{1}\frac{\mathrm{kJ}}{\mathrm{day}}=\mathrm{E}$
$\therefore \mathrm{E}={\mathrm{mc}}^{2}⇒\mathrm{m}=\frac{\mathrm{E}}{{\mathrm{c}}^{2}}$