NEET Physics Nuclei Questions Solved


Three α-particles and one β-particle decaying takes place in series from an isotope Ra88236. Finally the isotope obtained will be 
(a) X84220         (b) X86222
(c) X83224         (d) X83215

(c) By using nα=A-A'4 and nβ=2nα-Z+Z'

A'=A-4nα=236-4×3=224

and Z'=nβ-2nα+Z=1-2×3+88=83

Difficulty Level:

  • 12%
  • 12%
  • 73%
  • 6%
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