# NEET Physics Nuclei Questions Solved

If the mass number of an atom is A = 40 and its electron configuration is $1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^{6}3{\mathrm{s}}^{2}3{\mathrm{p}}^{6}$, the number of neutrons and protons in its nucleus will be
(a) 22, 18            (b) 18, 22
(c) 20, 20            (d) 18, 18

(a) Number of protons = 2 + 2 + 6 + 2 + 6 = 18
Number of neutrons = 40 – 18 = 22.

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