NEET Physics Nuclei Questions Solved


The nuclear reaction H12+H12He24 (mass of deuteron = 2.0141 a.m.u. and mass of He = 4.0024 a.m.u.) is

(a) Fusion reaction releasing 24 MeV energy
(b) Fusion reaction absorbing 24 MeV energy
(c) Fission reaction releasing 0.0258 MeV energy
(d) Fission reaction absorbing 0.0258 MeV energy

(a) Total mass of reactants =2.0141×2=4.0282 amu
Total mass of products =4.0024 amu
Mass defect = 4.0282 amu-4.0024 amu = 0.0258 amu

 Energy released E = 931×0.0258 = 24 MeV

Difficulty Level:

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  • 18%