NEET Physics Nuclei Questions Solved


The energy liberated on complete fission of 1 kg of U92235 is (Assume 200 MeV energy is liberated on fission of 1 nucleus) 
(a) 8.2×1010 J                           (b) 8.2×109 J
(c) 8.2×1013 J                           (d) 8.2×1016 J

(c) Mass of a uranium nucleus =92×1.6725×10-27+143×1.6747×10-27=393.35×10-27 kg

Number of nuclei in the given mass =1393.35×10-27=2.542×1024

Energy released =200×2.542×1024 MeV

=5.08×1026 MeV=8.135×1013J=8.2×1013J

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