NEET Physics Nuclei Questions Solved


To generate a power of 3.2 mega watt, the number of fissions of U235 per minute is
(Energy released per fission = 200MeV, 1eV=1.6×10-19 J 

(a) 6×1018         (b) 6×1017
(c) 1017              (d) 6×1016

(a) Number of fissions per second = Power outputEnergy released per fission=3.2×106200×106×1.6×10-19=1×1017

Number of fission per minute = 60×1017=6×1018

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