NEET Physics Nuclei Questions Solved


If 200 MeV energy is released in the fission of a single U235 nucleus, the number of fissions required per second to produce 1 kilowatt power shall be (Given 1 eV=1.6×10-19 J
(a) 3.125×1013           (b) 3.125×1014
(c) 3.125×1015           (d) 3.125×1016

(a) P=nEt1000=n×200×106×1.6×10-19tnt=3.125×1013

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