# NEET Physics Nuclei Questions Solved

In the nuclear reaction ${}_{92}\mathrm{U}^{238}\to {}_{\mathrm{z}}\mathrm{Th}^{\mathrm{A}}+{}_{2}\mathrm{He}^{4}$ , the values of A and Z are
(a) A = 234, Z = 94              (b) A = 234, Z = 90
(c) A = 238, Z = 94              (d) A = 238, Z = 90

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