NEET Physics Nuclei Questions Solved

(d) The given equation is ${}_2\mathrm{He}^4+{}_{\mathrm{Z}}\mathrm{X}^{{}_{\mathrm{A}}}\to {}_{\mathrm{z}+2}\mathrm{Y}^{\mathrm{A}+3}+\mathrm{A}$
Applying charge and mass conservation

4+A=A+3+x$\Rightarrow$x = 1$\Rightarrow$2+z = z+2+n$\Rightarrow$n = 0

Hence A is a neutron.