NEET Physics Nuclei Questions Solved


In nuclear reaction He42+XAZYA+3z+2+A, A denotes 
(a) Electron            (b) Positron
(c) Proton               (d) Neutron

(d) The given equation is He42+XAZYA+3z+2+A
Applying charge and mass conservation

4+A=A+3+xx = 12+z = z+2+nn = 0

Hence A is a neutron.

Difficulty Level:

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