NEET Physics Nuclei Questions Solved


The rest energy of an electron is

(a) 510 KeV            (b) 931 KeV
(c) 510 MeV            (d) 931 MeV

(a) Rest energy of an electron = mec2
Here me=9.1×10-31 kg and c = velocity of light
 Rest energy = 9.1×10-31×3×1082 joule
=9.1×10-31×(3×108)21.6×10-19eV=510 keV

 

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