The reactivity order of halides for dehydrohalogenation is 

1. R-F>R-Cl>R-Br>R-I

2. R-I>R-Br>R-Cl>R-F

3. R-I>R-Cl>R-Br>R-F

4.  R-F>R-I>R-Br>R-Cl

In ${\mathrm{S}}_{{\mathrm{N}}^2}$ reactions, the correct order of reactivity for the following compounds : ${\mathrm{CH}}_3\mathrm{Cl}$, ${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{Cl}$, ${\left({\mathrm{CH}}_3\right)}_2\mathrm{CHCl}$ and ${\left({\mathrm{CH}}_3\right)}_3\mathrm{CCl}$ is :

1. ${\mathrm{CH}}_3\mathrm{Cl}$>${\left({\mathrm{CH}}_3\right)}_2\mathrm{CHCl}$>${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{Cl}$>${\left({\mathrm{CH}}_3\right)}_3\mathrm{CCl}$

2. ${\mathrm{CH}}_3\mathrm{Cl}$>${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{Cl}$>${\left({\mathrm{CH}}_3\right)}_2\mathrm{CHCl}$>${\left({\mathrm{CH}}_3\right)}_3\mathrm{CCl}$

3. ${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{Cl}$>${\mathrm{CH}}_3\mathrm{Cl}$>${\left({\mathrm{CH}}_3\right)}_2\mathrm{CHCl}$>${\left({\mathrm{CH}}_3\right)}_3\mathrm{CCl}$

4. ${\left({\mathrm{CH}}_3\right)}_2\mathrm{CHCl}$>${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{Cl}$>${\mathrm{CH}}_3\mathrm{Cl}$>${\left({\mathrm{CH}}_3\right)}_3\mathrm{CCl}$

Action of RMgX with vinyl chloride gives:

1. alkane                                 

2. alkyne

3. alkene                                 

4. all of these

What would be the product formed when 1-bromo-3-chlorocyclobutane reacts with two equivalents of metallic sodium in ether?

1.   

2. 

3.    

4. 

X $\stackrel{{\mathrm{Cl}}_2}{\to }$ Benzotrichloride $\stackrel{\mathrm{Hydrolysis}}{\to }$ Y

X and Y respectievely are:

1. benzene, benzaldehyde

2. toluene, benzaldehyde

3. toluene, benzoic acid

4. benzene, benzoic acid

Benzene on reaction with a mixture of HNO₃ and H₂SO₄ followed by reaction of Cl₂/FeCl₃ gives:

1. 3-chloro -1 -nitrobenzene

2. 2-chloro -1 -nitrobenzene

3. 4-chloro -1 -nitrobenzene

4. a mixture of 2-chloro and 4-chloro -1 -nitrobenzene

A yellow precipitate is obtained when aqueous ${\mathrm{AgNO}}_3$ is added to a solution of the compound:

1. ${\mathrm{CCl}}_3\mathrm{CHO}$

2. ${\mathrm{CHI}}_3$

3. ${\mathrm{CHCl}}_3$ 

4. ${\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{CH}}_2\mathrm{Cl}$

In the following sequences of reactions;

${\mathrm{CH}}_3{\mathrm{CH}}_2{\mathrm{CH}}_2\mathrm{I}\stackrel{\mathrm{KOH}(\mathrm{alc}.)}{\to }$(A)$\stackrel{{\mathrm{Br}}_2}{\to }$(B)$\stackrel{{\mathrm{NaNH}}_2/{\mathrm{NH}}_3}{\to }$(C)

the end product (C) is:

1. alkene                                 

2. alkanol

3. alkyne                                   

4. alkyl amine

Which is gem dihalide?

1. ${\mathrm{CH}}_3.{\mathrm{CHBr}}_2$                           
2. ${\mathrm{CH}}_2\mathrm{Br}.{\mathrm{CH}}_2\mathrm{Br}$ 
3. ${\mathrm{CH}}_3.\mathrm{CHBr}.{\mathrm{CH}}_2\mathrm{Br}$                   
4. None of the above

Friedel-Craft's reaction of bromobenzene with methyl iodide gives:

1. o-bromotoluene                     

2. p-bromotoluene

3. o-and p-bromotoluenes             

4. m-bromotoluene