# NEET Physics Atoms Questions Solved

An electron jumps from the 4th orbit to the 2nd orbit of hydrogen atom. Given the Rydberg's constant R = . The frequency in Hz of the emitted radiation will be
(a) $\frac{3}{16}×{10}^{5}$           (b) $\frac{3}{16}×{10}^{15}$
(c) $\frac{9}{16}×{10}^{15}$          (d) $\frac{3}{4}×{10}^{15}$

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