# NEET Physics Thermodynamics Questions Solved

In the following P-V diagram two adiabatics cut two isothermals at temperatures T1 and T2 (fig.). The value of $\frac{{V}_{a}}{{V}_{d}}$ will be

(1) $\frac{{V}_{b}}{{V}_{c}}$

(2) $\frac{{V}_{c}}{{V}_{b}}$

(3) $\frac{{V}_{d}}{{V}_{a}}$

(4) VbVc

(1) For adiabatic process ${T}_{1}{V}_{b}^{\gamma -1}$ = Constant

For bc curve ${T}_{1}{V}_{b}^{\gamma -1}={T}_{2}{V}_{c}^{\gamma -1}$ or $\frac{{T}_{2}}{{T}_{1}}={\left(\frac{{V}_{b}}{{V}_{c}}\right)}^{\gamma -1}$ …..(i)

For ad curve ${T}_{1}{V}_{a}^{\gamma -1}={T}_{2}{V}_{d}^{\gamma -1}$ or $\frac{{T}_{2}}{{T}_{1}}={\left(\frac{{V}_{a}}{{V}_{d}}\right)}^{\gamma -1}$…..(ii)

From equation (i) and (ii) $\frac{{V}_{b}}{{V}_{c}}=\frac{{V}_{a}}{{V}_{d}}$

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